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IrinaK [193]
3 years ago
14

Calculate the magnitude of the average gravitational force between earth and the moon

Physics
1 answer:
zepelin [54]3 years ago
5 0
F = G mM / r^2, where 
<span>F = gravitational force between the earth and the moon, </span>
<span>G = Universal gravitational constant = 6.67 x 10^(-11) Nm^2/(kg)^2, </span>
<span>m = mass of the moon = 7.36 × 10^(22) kg </span>
<span>M = mass of the earth = 5.9742 × 10^(24) and </span>
<span>r = distance between the earth and the moon = 384,402 km </span>

<span>F </span>
<span>= 6.67 x 10^(-11) * (7.36 × 10^(22) * 5.9742 × 10^(24) / (384,402 )^2 </span>
<span>= 1.985 x 10^(26) N</span>
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A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s.
kherson [118]

Answer:

<em>a. The rock takes 2.02 seconds to hit the ground</em>

<em>b. The rock lands at 20,2 m from the base of the cliff</em>

Explanation:

Horizontal motion occurs when an object is thrown horizontally with an initial speed v from a height h above the ground. When it happens, the object moves through a curved path determined by gravity until it hits the ground.

The time taken by the object to hit the ground is calculated by:

\displaystyle t=\sqrt{\frac{2h}{g}}

The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:

\displaystyle d=v.t

The man is standing on the edge of the h=20 m cliff and throws a rock with a horizontal speed of v=10 m/s.

a,

The time taken by the rock to reach the ground is:

\displaystyle t=\sqrt{\frac{2*20}{9.8}}

\displaystyle t=\sqrt{4.0816}

t = 2.02 s

The rock takes 2.02 seconds to hit the ground

b.

The range is calculated now:

\displaystyle d=10\cdot 2.02

d = 20.2 m

The rock lands at 20,2 m from the base of the cliff

5 0
3 years ago
Discuss how the motion of the stunt cyclist relates to the forces acting on the stunt cyclist during the collision
ivolga24 [154]

Answer:

hello your question is incomplete hence I will give you a general answer on how a stunt cyclist performs his stunts successfully

answer ;

The stunt cyclist trying to perform some sort of stunt with the bicycle will be faced with some forces like the static fiction between the tires of the bicycle and wall and also a centripetal force.

In order to overcome the centripetal force the minimal grip of the bicycle must be equal to the weight and the speed at which the cyclist must go can be represented as :

V_{min} = \sqrt{\frac{r.g}{u} }

Explanation:

The stunt cyclist trying to perform some sort of stunt with the bicycle will be faced with some forces like the static fiction between the tires of the bicycle and wall and also a centripetal force.

In order to overcome the centripetal force the minimal grip of the bicycle must be equal to the weight and the speed at which the cyclist must go can be represented as :

V_{min} = \sqrt{\frac{r.g}{u} }

where ; r = radius of the tunnel where the stunt is to be performed

            g = gravitational speed

            u = coefficient of static friction

6 0
3 years ago
Which kind of wave is generated by a plucked guitar string as the molecules
olchik [2.2K]
The answer would be A.Transverse
3 0
3 years ago
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Which letter represent the location of the resister in this diagram?​
fenix001 [56]

Answer:

<h2>Letter which represent the resistance in this circuit diagram is</h2><h2>D</h2>

Explanation:

Here in this circuit diagram we know that

A = Battery

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4 years ago
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aleksley [76]

Answer:F = kq2/d2 ⇒

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Look up k in your physics book in appropriate units, and plug in the numbers. You should get q in coulombs.

Explanation:

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