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damaskus [11]
3 years ago
15

What is the density of an 800 gram object that occupies 200 cm 3 ?

Chemistry
1 answer:
vova2212 [387]3 years ago
8 0
Density = mass/volume = 800/200 =4 g/cm^3
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sveticcg [70]
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7 0
2 years ago
An unknown diprotic acid (H2A) requires 44.391 mL of 0.111 M NaOH to completely neutralize a 0.58 g sample. Calculate the approx
Anna [14]

Answer:

M=235.42g/mol

Explanation:

Hello!

In this case, given this is an acid-base neutralization and we are considering a diprotic acid, we can write the following mole-mole relationship:

2n_{acid}=n_{base}

It means that the moles of acid can be computed given the volume and concentration of NaOH:

n_{acid}=\frac{M_{base}V_{base}}{2} =\frac{0.044391L*0.111mol/L}{2} \\\\n_{acid}=2.46x10^{-4}mol

It means that the approximate molar mass of the acid is:

M=\frac{m_{acid}}{n_{acid}} \\\\M=\frac{m_{acid}}{n_{acid}} =\frac{0.58g}{2.46x10^{-3}mol}\\\\M=235.42g/mol

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3 years ago
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Dafna11 [192]

Answer:

Boron

Explanation:

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It means its atomic number is five and mass number is 5+6 = 11

8 0
3 years ago
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