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ludmilkaskok [199]
2 years ago
13

PlS hurry i'm timed

Chemistry
2 answers:
Ludmilka [50]2 years ago
6 0

Answer:

the answer is (moon)

Explanation:

my best guess based on internet research

Gennadij [26K]2 years ago
4 0

Answer:

Moon... I did the assignment just a little while ago...

Explanation:

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What is the Lewis Dot Diagram of gold?
ratelena [41]
Its structure is Au with one dot on top
6 0
3 years ago
2KI + Pb(NO3)2 → 2KNO3 + PbI2 Determine how many moles of KNO3 are created if 0.03 moles of KI are completely consumed.
ElenaW [278]
2:2 so the same proportion 
0,03

6 0
3 years ago
Read 2 more answers
A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W
Agata [3.3K]

Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

E^0_{[Ag^{+}/Ag]}=+0.80V

E^0_{[Cu^{2+}/Cu]}=+0.34V

In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

Oxidation half reaction (Anode) : Cu(s)\rightarrow Cu^{2+}(aq)+2e^-

Reduction half reaction (Cathode) : Ag^{+}(aq)+e^-\rightarrow Ag(s)

Thus the overall reaction will be,

Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

7 0
3 years ago
What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.0×1015Hz?
Anvisha [2.4K]
In order to emit electrons, the cesium will have to absorb photons. Each photon will knock out one electron by transferring its energy to the electron. Therefore, by the principle of energy conservation, the energy of the removed electron will be equal to the energy of the incident photon. That energy is calculated using Planck's equation:

E = hf

E = 6.63 x 10⁻³⁴ * 1 x 10¹⁵
E =  6.63 x 10⁻¹⁹ Joules

The electron will have 6.63 x 10⁻¹⁹ Joules of kinetic energy
3 0
3 years ago
7. List things that have LOTS of kinetic energy, and tell why.
vlabodo [156]

Answers: -

For high kinetic energy, the object must have high speed of movement.

1) An airplane has a lot of kinetic energy. Airplanes move at high speed and thus posses a lot of kinetic energy.

2) A bullet from a gun has a lot of kinetic energy due to the high speed of bullet.

3) A formula one car moving at high speeds have a lot of kinetic energy.

4) A train moving at high speed has lots of kinetic energy.

5) An asteroid has a lot of kinetic energy due to it's high speed.

6) A roller coaster moving at high speeds have a lot of kinetic energy.

7) A missile fired from a fighter plane has lots of kinetic energy.

7 0
3 years ago
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