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antoniya [11.8K]
3 years ago
14

A hydrate of iron (ii) sulfite is known to contain 44.26% mater. what is the correct name of the hydrate

Chemistry
1 answer:
stellarik [79]3 years ago
6 0
The correct name of the  hydrate iron (ii) sulfite  is  iron(ii)sulfite  heptahydrate
it is gotten  as below

find the % composition  of  FeSO4  = 100-44.26 =55.74 %

find the mole of FeSO4 and  H20
= % composition/molar mass

FeSo4 =55.74/151.9 = 0.367  moles
H2O = 44.26/18 =2.459  moles

find  the mole ratio  by diving   each mole  with smallest mole
FeSO4 = 0.367/0.367 = 1
H2O = 2.459/0.367 = 7

therefore the name is iron (ii) sulfite  heptahydrate is it has  seven water  molecules
  
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Sodium is a metal, Chloride is a non-metal.

Right off the bat, you know that in order for both of these atoms to achieve a full valence shell that the metal has to lose electrons, and the non-metal has to gain them.

Therefore, you have the transfer of electrons in this bond in order to form ions.
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3 years ago
How many moles of O2 are needed to react with 2.35 mol of C2H2?
Mrrafil [7]
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

2.35 mol C2H2 - x mol O2
2 mol C2H2 - 5 mol O2

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5 0
3 years ago
Read 2 more answers
3 points
VLD [36.1K]

Answer:

<h3>The answer is 8.29 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 19.30g/L

error = 20.9 - 19.3 = 1.6

We have

p(\%) =  \frac{1.6}{19.3}  \times 100 \\  = 8.290155440...

We have the final answer as

<h3>8.29 %</h3>

Hope this helps you

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3 years ago
Give another mixture of liquids that is separated on an industrial scale by fractional
iren [92.7K]

Answer:

dna or diabeties can be separated

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3 years ago
What is the mass of 7 x 10^28 atoms of Fe?
Nostrana [21]

Answer:

6 x 10⁶ g Fe

Explanation:

Step 1: Set up dimensional analysis

7 x 10²⁸ atoms Fe (1 mol Fe/6.02 x 10²³ atoms Fe)(55.85 g Fe/1 mol Fe)

Step 2: Multiply, divide, and cancel out units

atoms Fe and atoms Fe cancel out.

mol Fe and mol Fe cancel out.

We should be left with g Fe.

7 x 10²⁸/6.02 x 10²³ = 116279 mol Fe

116279(55.85) = 6.49 x 10⁶ g Fe

Step 3: Sig figs

There is only 1 sig fig in this problem.

6.49 x 10⁶ g Fe ≈ 6 x 10⁶ g Fe

4 0
3 years ago
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