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aivan3 [116]
3 years ago
6

A radioactive substance used in nuclear weapons decays at the rate of 3.33.3​% per year. calculate the​ half-life of the radioac

tive substance.
Chemistry
1 answer:
mylen [45]3 years ago
3 0
The amount of substance that is present after t years given that the half-life of the substance is h is calculated through the equation,

   A(t) = A(o)(0.5^t/h)

If after a year, the rate of decay is equal to 33.3% then,

   A(t)/A(o) = (1/3) = 0.5^(1/h)

The value of h from the equation is 0.63 years. 

Answer: 0.63 years
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Murrr4er [49]
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4 0
3 years ago
A 25 kg rock is placed in a graduated cylinder with water.the volume of the fluid is 18.3ml.calculate the density of the rock in
ipn [44]

Answer:

=> 1366.120 g/mL.

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 25 Kg

Volume (v) = 18.3 mL.

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

First let's convert 25 Kg to g;

1 Kg    = 1000 g

25 Kg = ?

= \frac{25 × 1000}{1}

= 25000 g

Substitute the values into the formula:

p =  \frac{25000 g}{18.3 ml}

= 1366.120 g/mL.

Therefore, the density (rho) of the rock is  1366.120 g/mL.

8 0
2 years ago
What is the density of lead (in g/cm^3 3 ) if a rectangular bar measuring 0.500 cm in height, 1.55 cm in width, and 25.00 cm in
Viktor [21]

Answer:

Density = 11.4 g/cm³

Explanation:

Given data:

Density of lead = ?

Height of lead bar = 0.500 cm

Width of lead bar = 1.55 cm

Length of lead bar = 25.00 cm

Mass of lead bar = 220.9 g

Solution:

Density = mass/ volume

Volume of bar = length × width × height

Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm

Volume of bar = 19.4 cm³

Density of bar:

Density = 220.9 g/ 19.4 cm³

Density = 11.4 g/cm³

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Answer:

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3 years ago
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