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Dimas [21]
3 years ago
6

What is the main purpose of the second paragraph?

Chemistry
1 answer:
Svetlanka [38]3 years ago
5 0
To explain your first paragraph which includes your thesis. The second paragrph supports your first pragraph
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Which of the following is an irreversible physical change?
Yuliya22 [10]

Answer:

b) sharpening a pencil

Explanation:

If you melt lead, boil water, or dissolve sugar in water, you can return all of them back to their original state. If you sharpen a pencil, you can't reattach the shavings as they were originally.

3 0
4 years ago
After the solution reaches equilibrium, what concentration of zn2 (aq remains?
Fantom [35]
According to sources, the most probable answer to this query is that when solutions reaches equilibrium, the amount of concentration of two or more matter combined in this solution becomes equal. 

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8 0
3 years ago
Cu + 2AgNO3 →
netineya [11]

Answer: 292.54g of Ag

Explanation:

Cu + 2AgNO3 →Cu(NO3)2 + 2 Ag

mass conc. Of Ag = n x molar Mass

Mass conc. Of Ag = 2 x 108 = 216g

From the equation,

63.5g of Cu produced 216g of Ag

Therefore, 86g of Cu will produce Xg of Ag. i.e

Xg of Ag = (86 x 216)/63.5 = 292.54g

5 0
3 years ago
V2 = (P1 × V1 × T2) (P2 × T1) A gas with a beginning pressure of 2 atm at a temperature of 300 K has a volume of 20 ml. What wil
rusak2 [61]

6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

V_1=20 ml

T_1=3

P_1=2 atm

T_2=200 K

P_2=4 atm

V_2=?

Using equation:

V_2 = \frac{P_1 X V_1 XT_2}{P_2 X T_1}

V_2 =\frac{2 atm  X 20 ml X200 K}{4 atm  X 300 K}

V_2 = 6.6 ml

Hence, 6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

Learn more about the ideal gas equation here:

#SPJ1

6 0
2 years ago
The acid dissociation constant, ___, is a quantitative measure of acid strength
8090 [49]

Answer:

The acid dissociation constant, _Ka__, is a quantitative measure of acid strength

Explanation:

6 0
3 years ago
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