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VikaD [51]
3 years ago
6

The table provides the number of valence electrons for each of the two atoms that form an ionic and a covalent compound. Which o

f the following statements is true about one of the compounds? Compound C is ionic because both atoms are in need of electrons. Compound D is covalent because both atoms are in need of electrons. Compound D is ionic because one atom is in need of electrons and the other needs to lose electrons. Compound C is covalent because one atom is in need of electrons and the other needs to lose electrons.

Chemistry
1 answer:
aev [14]3 years ago
3 0

Here we have to choose the correct statement among the given statements.

The true statement is-

Compound D is covalent because both atoms are in need of electrons.

The covalent compounds are those in which both the atom needs electrons and on the other hand ionic compounds are those in which one atom loose electron and other gain electron.

The atoms of the noble gas (except He) contains 8 electrons in their outermost shell. The high stability of the 8 electrons in the outermost shell of any atoms leads to the formation of covalent compound between two atoms.

Here the compound C posses two atoms atom 1 and atom 2 which posses 7 and 2 electrons respectively so atom 1 and atom 2 both needs electrons to get the 8 electrons in the outer shell. Thus it will be more ionic in nature.

The compound D posses two atoms having 6 and 5 valence electrons respectively. Thus atom 1 need 2 electrons and atom 2 needs 3 electrons to get the 8 electrons in the valence shell. so both the atom need electrons it will be covalent in nature.  

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820 g Li2SO4 is dissolved into 2500 mL of solution. What is the molar concentration?
Andreas93 [3]

Molarity is defined as the moles of solute per liter of solution. M=\frac{n}{V}. Where M is molarity, n is the number of moles and V is the volume. First we must find the molar mass of Li_2SO_4 which is 109.98 g/mol

Li_2SO_4= 2 \times Li_{Ar} + S_{Ar} + 4 \times O_{Ar}\\= (2 \times 6.941 + 32.1 + 4 \times 16.0) = 109.98 g/mol

820\ g\ Li_2SO_4 \times \frac{mol}{109.98\ g}= 7.46\ mol\ Li_2SO4

Then we find the molarity using above equation

M= \frac{n}{V} = \frac{7.46 mol}{2500ml} \times\frac{1000ml}{L} = 2.98\ M


6 0
4 years ago
How many atoms are in 3.20 moles of carbon
DIA [1.3K]

Answer:

19.264×10^{23} atoms are present in 3.2 moles of carbon.

Explanation:

It is known that one mole of each element is composed of Avagadro's number of atoms. This is same for all the elements in the periodic table.

So, as 1 mole of any element = Avagadro's number of atoms = 6.02×10^{23} atoms

It is as simple as understanding a dozen of anything is equal to 12 pieces of that object.

As here the moles of carbon is given as 3.20 moles, the number of atoms in this mole can be determined as below.

1 mole of carbon = 6.02 ×10^{23} atoms

Then, 3.20 moles of carbon = 3.20 × 6.02 ×10^{23} atoms

Thus, 19.264×10^{23} atoms are present in 3.2 moles of carbon.

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