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svetlana [45]
3 years ago
15

A weight watcher who normally weighs 400 N stands on top of a very tall ladder so she is one Earth radius above Earth's surface

(i.e. twice her normal distance from Earth's center). How much is her weight there? Group of answer choices
Physics
1 answer:
Troyanec [42]3 years ago
4 0

Answer:

100 N

Explanation:

Let us first find the mass of the person when they are on the earth's surface

F=G\frac{Mm}{r^{2} }\\

Now let us see how F changes if the distance between two masses is doubled

F_{1}  = G\frac{Mm}{(2r)^{2} } = \frac{1}{4} *G\frac{Mm}{r^{2} }

So when the distance of separation is doubled, the force of gravity between the two masses decreases by a factor of four

Therefore her new weight = 400 N/4 = 100 N

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Explanation:

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A hot air balloon rising vertically is tracked by an observer located 3 miles from the lift-off point. At a certain moment, the
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Answer:

\frac{dy}{dt}=1.2\frac{mi}{min}

Explanation:

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Differentiating (1) with respect to time, we get:

\frac{dy}{dt}=tan\theta\frac{dx}{dt}+xsec^{2}\theta\frac{d\theta}{dt}\\

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3 years ago
A trampoline has a spring constant of 3430 N/m how far will the trampoline sink when a 70 kg person steps on it
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3 0
3 years ago
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If the magnet is now pushed into the coil and then held stationary inside the coil describe fully what would you observe on the
alexira [117]

Answer:

E = q V B     describes the electric field induced

E Proportional to V B

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When V drops to zero the deflection must again be zero

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2 years ago
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Mumz [18]

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2 years ago
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