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Verizon [17]
4 years ago
8

A wire of length L and cross-sectional area A has resistance R.

Physics
2 answers:
lara31 [8.8K]4 years ago
4 0

Answer:

The resistance will be twice the original resistance

Explanation:

This is a fairly simple question, the formular for the resistance of a wire is given as

R = rho *length / area

Where R = resistance

Rho = resistivity

L = length

A = area

Since the density and area are constant I.e they do not change

R/ length = rho/ area

The initial length is given as L, when this length is stretched to twice its original length ,it becomes 2×L = 2L

Let x represent the resistance when the length is doubled

R/ L = x / 2L

x = 2LR / L ; dividing by L

We have that x = 2R ; twice the resistance

soldi70 [24.7K]4 years ago
4 0

Answer:

Explanation:

Given:

L2 = 2 × L1

Using the formula,

Resistivity, d = (R × A)/L

Where,

R = resistance

A = area

L = length

1. d1 = (R1 × A1)/L1

2. d2 = (R2 × A2)/L2

Equating both 1 and 2 together,

(R2 × A2)/L2 = (R1 × A1)/L1

(R2 × A2)/(2 × L1) = (R1 × A1)/L1

Assume A1 = A2,

R2 = [(R1 × A1) × 2 × L1]/(A1 × L1)

R2 = 2 × R1

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Svetllana [295]

Answer:

non linear square relationship

Explanation:

formula for centripetal force is given as

a = mv^2/r

here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have

a = constant × v^2

a α v^2

hence non linear square relationship

7 0
3 years ago
In which item is energy stored in the form of gravitational potential energy? A. A slice of bread B. A compressed spring C. An a
marysya [2.9K]

The things that determine the amount of an object's gravitational potential energy are ...

-- mass of the object

-- gravitational acceleration in the place where the object is

-- height of the object above the ground or the floor

A). <em>a slice of bread; </em> No.  It's still a slice of bread even if it's on the ground.

B. <em>A compressed spring; </em> No.  It's still a compressed spring even if it's on the ground.

C. <em>An apple on a tree</em>; <em>Yes !</em>  It can't be an apple on a tree if it's on the ground.  

D. <em>A stretched bow string</em>; <em>No.</em>  It's still a stretched bowstring even if it's on the ground.

3 0
3 years ago
Read 2 more answers
Satuarated solution changes into unsatuarated by heating give reason​
Crazy boy [7]

Answer:

Due to application of heat on a saturated solution, the interparticle space increases due to increase in the kinetic energy of the particles which allows more solutes to dissolve in the solution thereby making it unsaturated.

4 0
3 years ago
In any vector space au=bu implies a=b ? Trou or False​
mixas84 [53]

Answer:

False

Explanation:

(I guess if it were written "properly" it would be ax=bx implies a=b).

Given the axioms we were given, it would seem that the statement should be true, no?

A related statement -- also listed as false -- is that "in any vector space, ax=ay implies that x=y." Again, given the axioms we have.

5 0
3 years ago
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A force of 6.0 N is applied horizontally to a 3.0 kg crate initially at rest on a horizontal frictionless surface. After the cra
Savatey [412]

Answer:

a. Yes, because the acceleration of the crate is 2.0 m/s².

Explanation:

Given

Force = 6N --- f

Mass = 3kg --- m

Time = 1.5s --- t

Velocity = 3.0m/s --- v

Required

Does the system support F=ma

Yes, it does and this is shown below

The crate is initially at rest; so:

u = 0

Using the first equation of motion

v = u + at

Substitute values for v, u and t

3 = 0 + a*1.5

3 = 1.5a

Make a the subject

a = 3/1.5

a = 2

Using F = ma

Substitute values for F and m

6 = 3 * a

Divide both sides by 3

6/3 = 3/3 * a

2 = a

a = 2

In both cases:

a = 2

<em>Hence, option (a) is correct.</em>

6 0
3 years ago
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