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Verizon [17]
3 years ago
8

A wire of length L and cross-sectional area A has resistance R.

Physics
2 answers:
lara31 [8.8K]3 years ago
4 0

Answer:

The resistance will be twice the original resistance

Explanation:

This is a fairly simple question, the formular for the resistance of a wire is given as

R = rho *length / area

Where R = resistance

Rho = resistivity

L = length

A = area

Since the density and area are constant I.e they do not change

R/ length = rho/ area

The initial length is given as L, when this length is stretched to twice its original length ,it becomes 2×L = 2L

Let x represent the resistance when the length is doubled

R/ L = x / 2L

x = 2LR / L ; dividing by L

We have that x = 2R ; twice the resistance

soldi70 [24.7K]3 years ago
4 0

Answer:

Explanation:

Given:

L2 = 2 × L1

Using the formula,

Resistivity, d = (R × A)/L

Where,

R = resistance

A = area

L = length

1. d1 = (R1 × A1)/L1

2. d2 = (R2 × A2)/L2

Equating both 1 and 2 together,

(R2 × A2)/L2 = (R1 × A1)/L1

(R2 × A2)/(2 × L1) = (R1 × A1)/L1

Assume A1 = A2,

R2 = [(R1 × A1) × 2 × L1]/(A1 × L1)

R2 = 2 × R1

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I NEEEED HELPPPPPPP PLEASEEEE
monitta

Answer:

Below

Explanation:

1) To find the average velocity of an object you can use this formula :

     v = ∆displacement / ∆time

     v = 200 m / 5 s

     v = 40 m/s

The average velocity of the turtle is 40 m/s

2) To find the distance an object can travel you can use this formula :

     d = (∆velocity)(∆time)

     d = (20m/s)(5s)

     d = 100 m

The cheetah can run 100 meters in 5 seconds

3) To find the amount of time it takes for an object to move :

     t = ∆displacement / ∆velocity

     t = 5mi / 20 mph

     t = 0.25 h

It would take this car 0.25 h to travel 5 miles at 20 mph

4) To find how far an object can go :

     d = (∆velocity)(∆time)

     d = (20mph)(3h)

     d = 60 mi

The car can drive 60 miles driving 20 mph for 3 hours

5) To find how far an object can go :

     d = (∆velocity)(∆time)

     d = (20mph)(30min)

     d = (20mph)(0.5h)

     d = 10 mi

The car can drive 10 miles driving 20mph for 30 minutes

6) To find how long it would take :

     t = ∆displacement / ∆velocity

     t = 10 m / 50 m/s

     t = 0.2 s

It would take the train 0.2 seconds for a train to travel 10 m at 50 m/s

7) To find how far :

     d = (∆velocity)(∆time)

     d = (670,000,000 mph)(1 yr)

     d = (670,000,000 mph)(8760 h)

     d = 5869200000000 mi

1 light year is 5869200000000 miles

Hope this helps! Best of luck <3

6 0
3 years ago
The product of voltage times amperage is known as what?
Usimov [2.4K]

Answer:

Power=V*I which corresponds to the second option shown: "voltage times amperage"

Explanation:

The electric power is the work done to move a charge Q across a given difference of potential V per unit of time.

Since such electrical work is the product of the potential difference V times the charge that moves through that potential, and this work is to be calculated by the unit of time, we need to divide the product by time (t) which leads to the following final simple equation

Power=\frac{V\,Q}{t} =V\,\frac{Q}{t} = V\, I

5 0
3 years ago
If a specimen was being viewed using a 20x objective lens and 10x ocular lens, what would be the total magnification
Paraphin [41]

Answer:

As Per Given Information

20x objective lens was used by specimen

10x ocular lens was also used by him.

we have to find the total magnification.

For calculating the total magnification we 'll simply do multiplication

Total Magnification = 20x × 10x

Total Magnification = 200x

So , the total magnification will be 200x .

6 0
2 years ago
How fast must the space shuttle go to cover 20,000 meters in 4.0 seconds?
Advocard [28]

Answer:

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Explanation:

7 0
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IRISSAK [1]

The solution to this task is f00king Dis.

6 0
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