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Ghella [55]
4 years ago
9

WILL GIVE BRAINLIEST

Chemistry
1 answer:
HACTEHA [7]4 years ago
4 0

Answer:

12) In the ball and stick model, an orange ball representing the phosphorus atom and three green balls representing chlorine atoms are connected by means of sticks that are coloured halfway green and orange respectively to represent the shared electrons between phosphorus and chlorine with the chlorine atoms forming the base of a triangular pyramid while the phosphorus atom forms the top of the pyramid.

13) The scientist will have 6 grams of product as before but will have two grams of unreacted copper atoms because the mass ratio of copper to sulfur in this reaction is 2:1

Explanation:

12) Phosphorus trichloride has a trigonal pyramidal structure and is composed of three atoms of chlorine and one atom of phosphorus.

In the ball and stick model, an orange ball representing the phosphorus atom and three green balls representing chlorine atoms are connected by means of sticks that are coloured halfway green and orange respectively to represent the shared electrons between phosphorus and chlorine with the chlorine atoms forming the base of a triangular pyramid while the phosphorus atom forms the top of the pyramid.

13) The reaction between copper and sulfur to form copper sulfide is shown in the equation below:

Cu + S ---> CuS

1 mole of copper reacts with 1 mole of sulfur to produce 1 mole of copper sulfide

molar mass of copper = 64 g/mol; molar mass of sulfur = 32 g/mol, molar mass of copper sulfide = 96 g/mol

mass ratio of copper to sulfur = 63 g/ 34 g = 2

This means that 2 grams of copper will react with 1 g of sulfur to produce 3 grams of product. similarly, 4 g of copper will react with 2 g of sulfur to produce 6 grams of product.

Therefore 6 g of of copper will react with 3 g of sulfur. However, since the amount of sulfur available for reaction is 2 g only, 2 g of copper will be left unreacted after 4 g has reacted completely with 2 g of sulfur to produce 6 g of copper sulfide.

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For the reaction below determine the ▲H for the reaction and state whether the reaction was endothermic or exothermic. Show your
scoundrel [369]

Answer:exothermice

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6 0
2 years ago
Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict whet
Sloan [31]

The given reaction is as follows:

2NO (g) + O₂ (g) = 2NO₂ (g), ΔH = -114 kJ

It is known that dSsurr = -dHsys / T (Temp = 355 K)

So,  dSsurr = - (-114 × 1000) / 355

dSsurr = +321.12 J/K

Hence, the value of dSsurr is +321.12 J/K

For a reaction to be spontaneous, dG<0,

Also dStotal = dSsys + dSsurr > 0

It is known that dG = dHsys - TdSsys,

Now let us assume,

dG<0

Also, dStotal = dSsys + dSsurr > 0

(-114 × 1000) - (355 × dSsys) <0

355 × dSsys > -114 × 1000

dSsys > -321

dSsys >dSsurr

dSsys + dSsurr > 0

dStotal > 0

Thus, the assumption is correct, and the given reaction is spontaneous. Hence, the final answer is Ssurr = +321 J/K reaction is spontaneous.



8 0
3 years ago
What state of matter has more mass?​
antoniya [11.8K]

Answer:

please mark as brainliest!!

Explanation:

ans: gas

The same number of particles in a gas spread further apart than in the liquid or solid states. The same mass takes up a bigger volume . This means the gas is less dense. Density also depends on the material.

6 0
3 years ago
Read 2 more answers
Can anyone help me with these I’m really co fused on what to do it’s for chemistry?
liq [111]

Answer:

It's just asking you to rearrange to equations to get what you want, so no numbers involved it's just teaching you the basics.

Explanation:

3 0
4 years ago
How many grams of carbon dioxide are created from the complete
ololo11 [35]

Answer:

<u>167.2 g</u>

Explanation:

Known

VC4H10 = 21.3

T = 0.00 C (convert to Kelvin: 273 K)

P = 1.00 atm

Unknown

m = ?g

1. <u>Write the balanced chemical equation</u>

1 C4H10 + 1O2  ----->  4 CO2 + 5 H2O

2. <u>Find the volume ratio of Carbon Dioxide to Butane </u>

1 C4H10   4 CO2  = 4 volumes CO2 / 1 volume C4H10

3.<u> Multiply by the known volume of n (butane)</u>

21.3 L C4H10  x  4 volumes CO2 / 1 volume C4H10 = 85.2 L C4H10

4. <u>Use ideal gas law</u>

PV = nRT   solve for n  ----> n = PV/RT

n= (1.00 atm) (85.2 L) / (0.0821 L atm/mol K) (273)  = 3.80 mol CO2

5.<u> Find molar mass of CO2</u>

1 C x 12 + 2 O x 16 = 44.00

6. <u>Multiply the ideal gas law solution (3.80) by molar mass CO2 (44.00)</u>

3.80 mol CO2 x 44.00 g CO2

= 167.2 g CO2  

7 0
3 years ago
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