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blsea [12.9K]
3 years ago
12

A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the ca

binet is used to store bottles of tetrahydrofuran, carbon tetrachloride, pentane, dimethyl sulfoxide, and acetone. The chemist plans to try to identify the unknown liquid by measuring the density and comparing to known densities. First, from his collection of Material Safety Data Sheets (MSDS), the chemist finds the following information: liquid density of tetrahydrofuran 0.89·gcm^−3, carbon tetrachloride 1.6·gcm^−3, pentane 0.63·gcm^−3, dimethyl sulfoxide 1.1·gcm^−3, acetone 0.79·gcm^−3. Next, the chemist measures the volume of the unknown liquid as 0.852L and the mass of the unknown liquid as 938.g . Calculate the density of the liquid. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
lord [1]3 years ago
8 0

Answer:

DMSO

Explanation:

Volume of unknown liquid = 0.852L = 852mL or 852cm^3

Mass of unknown liquid = 938g

Density of unknown liquid = Mass of liquid / Volume of liquid

                                            = 938 / 852 = 1.100g/cm^3

From the given other data, the unknown liquid is Dimethyl sulfoxide (DMSO) as the MSDS of the mentioned liquid has been given 1.1g/cm^3

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For every system, according to the law of conservation of energy "energy is neither created nor destroyed but transformed from one form to another".

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The equation for carbon-14 emission by Radium-223 nuclei is given below:

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Elements are arranged in different groups according to the number of Valence electrons they have.

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