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likoan [24]
3 years ago
13

Help me please!! I need help!! Please !!

Mathematics
1 answer:
nikklg [1K]3 years ago
7 0

Answer:

Option 3 - 4/3

Step-by-step explanation:

When solving equations, we use inverse operations. The inverse of 3/4 is the reciprocal 4/3. Option 3 is the solution.

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Evaluate f(x)3x + 8 for x = 1.<br><br> A. -11<br> B. 5<br> C. 11<br> D. 3
mariarad [96]

Answer:11

Step-by-step explanation:

f(x)=3x+8

f(1)=3(1)+8

f(1)=3+8

f(1)=11

5 0
3 years ago
A hummingbird can fly between 0.34 and 0.81 miles per minute. Create an inequality to
Sergeu [11.5K]

Answer: .34 ≤ x ≤ .81

Step-by-step explanation:

An inequality is writted like __ ≤ x ≤ ___

Since the humming bird can fly between .34 and .81 we use the the less than or equal to sign because it can fly max .81 mpm or less than that. with a minimum speed of .34 mpm.

3 0
3 years ago
Find the sum. write each mixed number in simplest form 4 7/8 + 5 1/4
levacccp [35]
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3 0
3 years ago
Read 2 more answers
If a = 0.3 and b =0.5, what is the value of a+b?
Alborosie

Answer=

D

Step-by-step explanation

because of the dot/line at the top of the number it means it is a continuous same number

for example, 0.3 with a dot/line on top means it is 0.333333...

so 0.55...+0.33...=0.88...

and as it is a decimal that is in the range of 1-100 its like a percentage so it is 88/100

7 0
2 years ago
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A rescue helicopter flew from its home base for 35 kilometers on a course of 330 degrees to pick up an accident victim. It then
artcher [175]
I've drawn a triangle to represent the journey (see attached.

The angle from Home to Victim to Hospital is:

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Using the cos rule, we can solve for angle b:

a^2 = b^2 +c^2 - 2bccosA&#10;\\35^2 = 31.22...^2+25^2-2(31.22...)(25)cosb&#10;\\1225 = 975 + 625 - 1561.249...cosb&#10;\\-375 = -1561.249...cosb&#10;\\b = cos^{-1}( \frac{-375}{-1561.249...}) &#10;\\b = 76.1...

So the bearing the helicopter has to travel is:

270 - 76.1 = <u>193.9 degrees (1 dp)</u>

And the distance it travels is <u>31.2 km (1 dp)</u>








5 0
3 years ago
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