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diamong [38]
3 years ago
13

2H2S + 3O2 2SO2 + 2H2O Which option gives the correct mole ratios? H2S:SO2 = 2:2 and O2:H2O = 3:2 H2S:SO2 = 2:3 and O2:H2O = 3:2

H2S:SO2 = 4:4 and O2:H2O = 5:4 H2S:SO2 = 4:6 and O2:H2O = 4:4
Chemistry
1 answer:
UkoKoshka [18]3 years ago
7 0

<u>Correct Answer:</u><u> Option (A) </u>

H₂S : SO₂ = 2:2 and,

O₂: H₂O = 3:2

Explanation:

The mole ratio is the ratio of coefficients of the compounds involved in the reaction. <u>R</u><u><em>eactants,</em></u><u> as on the left hand side of the chemical reaction which reach to for</u>m new products.

In the given reaction,

2H₂S + 3O₂ ⇒ 2SO₂ + 2H₂O

<u>The reactants are :</u> H₂S (hydrogen sulphide) & O₂ (oxygen)

<u>The products are :</u> SO₂ (sulphur dioxide) & H₂O (water)

  1. 2 moles of hydrogen sulphide react with 3 moles of oxygen
  2. 2 moles of sulphur dioxide & 2 moles of water are produced

Therefore correct option is

H₂S : SO₂ = 2:2 and,

O₂: H₂O = 3:2

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The amount of the solute present in the given solution is called the concentration. The best way to represent the concentration of the solution is \rm [K_{2}CrO_{4}].

<h3>What is molar concentration?</h3>

Molar concentration is the molarity of the solution that is the measure of the concentration of the solute dissolved in the solution.

The formula for calculating molar concentration is given as,

\rm Molarity = \dfrac{\text{moles of solute}}{\text{Solution in L}}

The concentration of any substance is represented in the square bracket like \rm [X] or  \rm [K_{2}CrO_{4}].

Therefore, option B. \rm [K_{2}CrO_{4}] is the representation of the concentration.

Learn more about the molarity here:

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2 years ago
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Answer:def has to be someone you loved by Lewis Capaldi

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7 0
3 years ago
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Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. nh4cl cobr3 k2so
Illusion [34]
Answer: CoBr3 < K2SO4 < NH4 Cl

Justification:

1) The depression of the freezing point of a solution is a colligative property, which means that it depends on the number of particles of solute dissolved.

2) The formula for the depression of freezing point is:

ΔTf = i * Kf * m

Where i is the van't Hoof factor which accounts for the dissociation of the solute.

Kf is the freezing molal constant and only depends on the solvent

m is the molality (molal concentration).

3) Since, you are assuming equal concentrations and complete dissociation of the given solutes, the solute with more ions in the molecular formula will result  in the solution with higher depression of the freezing point (lower freezing point).

4) These are the dissociations of the given solutes:

a) NH4 Cl (s) --> NH4(+)(aq) + Cl(-) (aq) => 1 mol --> 2 moles

b) Co Br3 (s) --> Co(3+) (aq) + 3Br(-)(aq) => 1 mol --> 4 moles

c) K2SO4 (s) --> 2K(+) (aq) + SO4 (2-) (aq) => 1 mol --> 3 moles

5) So, the rank of solutions by their freezing points is:

CoBr3 < K2SO4 < NH4 Cl
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3 years ago
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Where did you put H an He? What are your reasoning for placement?
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Answer:

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2 years ago
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In a beta emission, the mass number of the daughter nucleus remains unchanged while the atomic number of the daughter nucleus increases by one unit. The following are isotopes produced when the following undergo beta emission;

1) potassium-42  ------> Ca - 42

2) iodine-131 ------------> Xe - 131

3)  iron-52 ---------------> Co - 52

4)  sodium-24 -----------> Mg -24

The daughter nucleus formed after beta emission is found one place after its parent in the periodic table.

Regarding the stability of the daughter nuclei, a nucleus is unstable if the neutron-proton ratio is less than 1 or greater than 1.5.

Hence, the following daughter nuclei are stable; Ca - 42, Xe - 131, Mg -24.

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