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Lemur [1.5K]
3 years ago
13

The fundamental sedimentary rock unit is called a. layer formation group bed

Chemistry
2 answers:
Evgesh-ka [11]3 years ago
8 0
<h3><u>Answer;</u></h3>

Formation

<h3><u>Explanation;</u></h3>
  • <em><u>Formation is the fundamental sedimentary rock unit which can normally be traced for long distance.</u></em>
  • <em><u>Sedimentary are one of the major types of rocks which results from deposition followed by cementation of mineral or organic particles on the ocean floor or other bodies on the surface of the earth.</u></em>
  • Formation is the fundamental sedimentary rock unit. These types of rocks are formed from deposition of sediment out of air, water, ice, gravity or water flows carrying suspended particles that form from weathering process.
Dimas [21]3 years ago
6 0

The fundamental sedimentary rock unit is called

a. layer formation group bed

The fundamental sedimentary rock unit which can normally be traced for long distances is the formation. The answer is letter B.

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Two or more atoms joined together form a _______
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Answer:

When two atoms join together they make compounds

Explanation:

A molecule is formed when two or more atoms join together chemically. If atoms combine that are of two or more different elements, we call that a compound. All compounds are molecules, but not all molecules are compounds.

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You are driving west on highway 510 in a European car. The speed limit for this portion of the highway is 50 miles per hour. You
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4 years ago
Explain why hydrogen and oxygen are considered elements whereas water is not considered an element.
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5 0
4 years ago
Read 2 more answers
FeSO4 • 7H2O
Mrac [35]

Answer:

1. Percent by mass of H₂O = 45.3%

2. Percent by mass of anhydrous Salt (FeSO₄) = 54.7 %

Explanation:

Data Given

Formula of the Molecule = FeSO₄ • 7H₂O

% by mass water (H₂O) = ?

% by mass FeSO₄ = ?

________________________________________

> First of all find the atomic masses of each component in a molecule

For H₂O atomic masses are given below

H = 1 g/mol

O = 16 g/mol

> Then find the total mass of H₂O in haydrated salt

7H₂O = 7 (2x1 +1x16) g/mol

7H₂O = 7 (2+16) g/mol

7H₂O = 7 (18) g/mol

7H₂O = 126 g/mol

> find total Molar Mass of Molecule:

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 16x4] + 7(2+16)

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = 278

Now to find the mass by percent of H₂O

Formula used to find the mass by percent of a component

Percent composition of  H₂O = mass of H₂O in Molecule / molar mass of FeSO₄ • 7H₂O x 100%  

Put the values

Percent by mass of H₂O = 126 (g/mol) / 278 (g/mol) x 100%

Percent by mass of H₂O = 0.4532 x 100%

Percent by mass of H₂O = 45.3%

_______________________________________________

> First of all find the atomic masses of each component in a molecule

For anhydrus salt (FeSO₄) atomic masses are given below

Fe = 56 g/mol

S= 32 g/mol

O = 16 g/mol

> Then find the total mass of FeSO₄ in haydrated salt

FeSO₄ = (56x1 + 32 + 4x16) g/mol

FeSO₄ = ( 56 + 32 + 64) g/mol

FeSO₄ = 152 g/mol

> find total Molar Mass of Molecule:

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 16x4] + 7(2+16)

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = 278

Now to find the mass by percent of FeSO₄

Formula used to find the mass by percent of a component

Percent composition of  FeSO₄ = mass of FeSO₄ in Molecule / molar mass of FeSO₄ • 7H₂O x 100%  

Put the values

Percent by mass of FeSO₄ = 152 (g/mol) / 278 (g/mol) x 100%

Percent by mass of FeSO₄ = 0.547 x 100%  

Percent by mass of FeSO₄ = 54.7 %

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