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Lemur [1.5K]
3 years ago
13

The fundamental sedimentary rock unit is called a. layer formation group bed

Chemistry
2 answers:
Evgesh-ka [11]3 years ago
8 0
<h3><u>Answer;</u></h3>

Formation

<h3><u>Explanation;</u></h3>
  • <em><u>Formation is the fundamental sedimentary rock unit which can normally be traced for long distance.</u></em>
  • <em><u>Sedimentary are one of the major types of rocks which results from deposition followed by cementation of mineral or organic particles on the ocean floor or other bodies on the surface of the earth.</u></em>
  • Formation is the fundamental sedimentary rock unit. These types of rocks are formed from deposition of sediment out of air, water, ice, gravity or water flows carrying suspended particles that form from weathering process.
Dimas [21]3 years ago
6 0

The fundamental sedimentary rock unit is called

a. layer formation group bed

The fundamental sedimentary rock unit which can normally be traced for long distances is the formation. The answer is letter B.

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The correct name for hno2 is ________. nitrous acid hyponitrous acid nitric acid pernitric acid hydrogen nitrate
balu736 [363]
Nitrous Acid.

Hyponitrous acid: H2N2O2

Nitric acid: HNO3

Pernitric acid: HNO


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A well-insulated cup of water is too hot to make tea, so you mixed it with an equal amount of cool water to lower the temperatur
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Answer:

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3 years ago
How many Grams would he present if 1 mole sample of sodium were collected?
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8 0
3 years ago
What observations led to the periodic law? what observations led to the periodic law? observation that certain elements possess
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7 0
3 years ago
Potassium permanganate(KMnO4) reacts with oxalic acid (H2C2O4) in aqueous sulfuric acid according to: 2KMnO4 5H2C2O4 3H2SO4-&gt;
Andru [333]

Answer:

57.3mL of 0.250M KMnO4 are required

Explanation:

3.225g of oxalic acid are:

3.225g×(1mol / 90.03g) = <em>0.03582mol of oxalic acid</em>

Based on the reaction, 5 moles of oxalic acid react with 2 moles of KMnO4, thus, for a complete reaction of oxalic acid you need:

0.03582mol of oxalic acid × (2mol KMnO4 / 5mol Oxalic Acid) = <em>0.01433mol of KMnO4</em>

<em />

If concentration of KMnO4 is 0.250M, liters in 0.01433mol are:

0.01433mol × (1L /0.250mol) = 0.0573L ≡<em> 57.3mL of 0.250M KMnO4 are required</em>

<em></em>

I hope it helps!

5 0
3 years ago
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