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algol13
3 years ago
13

Imagine that you meet with the team of scientists who assembled the graphs in part B. What questions would you ask the team abou

t the data presented?

Chemistry
2 answers:
worty [1.4K]3 years ago
8 0

Answer:

I will ask when they made this graphics, how they measured the gas and how this affected the climate change

<u><em>BRAINLIEST</em></u>

Zielflug [23.3K]3 years ago
4 0

Answer:

They made this graphics, how they measured the gas and how this affected the climate change horribly.

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D. She is not right, because there will be more successful collisions

between reactants in the concentrated solutions.

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Which 2 elements make up more than 80% of the atoms found in the Earth's crust​
mars1129 [50]

oxygen and silicon I believe

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Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty fo
jarptica [38.1K]

Answer:

a. Too close to zero

b. ΔS > 0

c. Too close to zero

d. ΔS < 0

e.  ΔS > 0

Explanation:

In order to answer this question we need to compare the change in number of mol in the gas state for the products vs the reactants.

An increase in number moles gas leads to a positive change in entropy. Conversely a decrease will mean ΔS is negative.

Now we can solve the parts in this question.

a. H₂ (g) + F₂ (g)   ⇒  2 HF (g)

We have no change in the number of moles gas products minus reactants. Therefore is too close to zero to decide since there is no change in mol gas.

b. 2 SO₃ ( g) ⇒ 2 SO₂ (g) + O₂ (g)

We have three moles of gas products starting with 2 mol gas SO₂, therefore ΔS is positive.

c. CH₄ (g) + 2 O₂ (g)   ⇒ CO₂ (g) + 2 H₂O (g)

Again, we have the same number of  moles gas in the products and the reactants (3), and it is too close to zero to decide

d.  2 H₂S (g) + 3 O₂(g) ⇒ 2 H2O (g) + 2 SO₂ (g)

Here the change in number of moles gas is negative ( -1 ), so will expect ΔS < 0

e. 2H₂O₂ (l)   ⇒ 2H₂O(l) +- O2(g)

Here we have 1 mol gas and 2 mol liquid  produced from 2 mol liquid reactants, thus the change in entropy is positive.

3 0
3 years ago
An open flask sitting in a lab refrigerator looks empty, but it is actually filled with a mixture of gases called air. If the fl
ira [324]

Answer:

9.39 × 10²² molecules

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P . V = n . R . T

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V is the volume

R is the ideal gas constant

T is the absolute temperature (standard temperature = 273.15 K)

n=\frac{P.V}{R.T} =\frac{1atm.3.50L}{(0.08206atm.L/mol.K).273.15K} =0.156mol

There are 6.02 × 10²³ molecules in 1 mol (Avogadro's number). Then,

0.156mol.\frac{6.02\times10^{23}molecules}{mol} =9.39\times10^{22}molecules

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