<span>Generally, a hydrogen bond can be characterized as a proton shared by two lone electron pairs. It occurs when a hydrogen (H) atom, covalently bound to a highly electronegative atom such as nitrogen (N), oxygen (O), or fluorine (F), experiences the electrostatic field of another highly electronegative atom nearby.
Among the choices in the bond (-N...H-O) one side of the Hydrogen is bonded to a highly electronegative atom with a lone pair (-N) and the other side is directly bonded with a highly electronegative atom (O-).
So -N...H-O- shows a hydrogen bond.</span>
<u>Answer:</u>
The disposal method used for high-level nuclear waste Concentrate and contain
<u>Explanation:</u>
High intensity nuclear waste is an underlying issue for the world where the generated nuclear waste is one side very hazardous and on other side would help us in many viable processes but the negative sides of a consequence just outnumber the positive sides of the situation.
Concentrate and contain is a waste disposable method which enables the nuclear waste to be preserved and isolated and later be used when the time comes. Other methods would not be suggested because they could cause a huge amount of dangerous radioactivity in oceans which is often harmful for people.
Answer:
The balanced chemical reaction of combustion of methane is:
734 liters of carbon dioxide gas is produced. .
Explanation:
The balanced chemical reaction of combustion of methane is:
Mass of methane gas = 0.500 kg = 500 g (1 kg= 1000 g)
Moles of methane = 
According to reaction, 1 mole of methane gas gives 1 mole of carbon dioxide gas. Then 31.25 moles of methane will give :
of carbon dioxide
Using ideal gas equation:
PV = nRT
where,
P = Pressure of gas = 
V = Volume of gas =?
n = number of moles of carbon dioxide gas = 31.25 mol
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas =13.0°C=13.0+273.15 K= 286.15 K
Putting values in above equation, we get:
V = 734.15 L ≈ 734 L
734 liters of carbon dioxide gas is produced. .
Answer:
PV=nRT where P=pressure in atm, V=volume is liters, n=numbber of moles, R=gas constant, 0.08206 L-atm/mole KL, and T=temperature in K (273 + C). So (5.67atm)(99.39L)=n(0.08206 L-atm/mol.K)(328.94K), solve for n, the number of moles, n=20.9 moles.
Explanation:
