A rectangle....unless it isn't a photo taken from a weird angle....but thats a rectangle.
Answer:
easey, sub them
(x,y)
see if true
(0,1), 2(0)+1>-4, 1>-4, true
(4,-12), 2(4)+-12>-4, 8-12>-4, -4>-4, false
(5,-12), 2(5)+-12>-4, 10-12<-4, -2>-4, true
(-1,-1), 2(-1)+-1>-4, -2-1>-4, -3>-4, true
(-3,0), 2(-3)+0>-4, -6>-4, false
answers are
(0,1)
(5,-12)
(-1,-1)
Hopefully that helped you a little bit :)
Combine like terms
9r+r=10r^2
7b+b=8b^2
10+10r^2+8b^2+4n
Answer:
139,999
Step-by-step explanation:
If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999
