Name a mammal that lives in the ocean

A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glo

allsm [11]

Answer:

PART A: 412.98 nm

PART B: 524.92 nm

Explanation:

The equation below can be used for a diffraction grating of nth order image:

n*λ = d*sinθ $_{n}$

Therefore, for first order images, n = 1 and:

λ = d*sinθ $_{1}$ .

The angle θ $_{1}$ can be calculated as follow:

tan θ $_{1}$ = 9.95 cm/15.0 cm = 0.663 and

θ $_{1}$ = $tan^{-1}$ (0.663) = 33.56°

Thus: d =λ/sin θ $_{1}$ = 461/sin 33.56° = 833.97 nm

PART A:

For a position of 8.55 cm:

tan θ $_{1}$ = 8.55 cm/15.0 cm = 0.57 and

θ $_{1}$ = $tan^{-1}$ (0.57) = 29.68°

Therefore:

λ =d*sin θ $_{1}$ = 833.97*sin 29.68° = 412.98 nm

PART B:

For a position of 12.15 cm:

tan θ $_{1}$ = 12.15 cm/15.0 cm = 0.81 and

θ $_{1}$ = $tan^{-1}$ (0.81) = 39.01°

Therefore:

λ =d*sin θ $_{1}$ = 833.97*sin 39.01° = 524.92 nm

6 0

3 years ago

Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.2

Rina8888 [55]

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a : C has $SP^{2}$ O has $SP^{2}$ .

Explanation : The orbitals of oxygen and carbon which are involved in $SP^{2}$ hybridization to form sigma bonds. This is observed at 'a' position in the citric acid molecule.

Answer 2) π Bond a: C has π orbitals and O also has π orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b: O $SP^{3}$ H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen $SP^{3}$ hydrogen atoms in it. It has $SP^{3}$ hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c: C is $SP^{3}$ O is also $SP^{3}$

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of $SP^{3}$ hybridized bonds.

Answer 5) Bond d: C atom has $SP^{3}$ C atom has $SP^{3}$

Explanation : At the position of 'd' the bonding between two carbon atoms is found to be $SP^{3}$ . Therefore, the orbitals that undergo $SP^{3}$ hybridization are $SP^{3}$ .

Answer 6) Bond e : C1 containing O $SP^{2}$

C2 is $SP^{3}$

Explanation : The carbon atom which contains oxygen along with a double bond has $SP^{2}$ hybridized orbitals involved in the bonding process; whereas the carbon at C2 has $SP^{3}$ hybridized orbitals involved during the bonding. This is for the 'e' position.

7 0

4 years ago

Which unstable element is used to determine the age of volcanic rock?

77julia77 [94]

Answer:

Potassium.

Explanation:

Therefore, the answer is Potassium. You might think, that because we were talking about Argon as well, the answer is both of them, but no. Everything starts with Potassium but it decays into Argon during the process.

6 0

3 years ago

Read 2 more answers

It’s laundry day at Dan’s house, so he plugs in his electric iron. What transformation of energy takes place inside the iron?

Olegator [25]

The answer is D because it uses the electrical energy from the wall to create heat (Thermal) energy for the clothes

6 0

4 years ago

Read 2 more answers

Use the following balanced reaction to solve:

Naily [24]

Answer: 60.7 g of $PH_3$ will be formed.