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Ostrovityanka [42]
3 years ago
7

Which factors affect heat transfer between a warm and a cool substance?

Physics
1 answer:
andrey2020 [161]3 years ago
5 0

Answer: B

Explanation:

It's not the time it took to heat the substance, so that rules out A and C.

This means that we only have to choose between

B. the area of contact

D. the area of the substances

(since everything else in each of those answers are the same)

Area of contact matters more (e.g. an object with greater surface area is exposed to the air more, will lose/gain heat quicker than an object with less surface area).

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A wildlife researcher is tracking a flock of geese. The geese fly 4.0km due west, then turn toward the north by 40 degrees and f
BaLLatris [955]

Answer:

(a). The distance from the initial position is 6.68 km.

(b).  The magnitude of their displacement is 7.05 km.

Explanation:

Given that,

Geese fly 4.0 km due west, then turn to north by 40° and fly another 3.5 km.

(a). We need to calculate the distance from the initial position

Using formula of distance

D=AB+BC\cos\theta

Put the value into the formula

D=4.0+3.5\cos40

D=6.68\ km

(b). We need to calculate the magnitude of their displacement

Using formula of displacement

AC=\sqrt{CD^2+AD^2}

AC=\sqrt{(3.5\sin40)^2+(6.68)^2}

AC=7.05\ Km

Hence, (a). The distance from the initial position is 6.68 km.

(b).  The magnitude of their displacement is 7.05 km.

8 0
3 years ago
Read 2 more answers
Why do many species that existed 35 million years ago no longer exist​
GenaCL600 [577]

Answer:

There are several reasons for the extinction of species. Some of these can include climate change, natural disasters, environmental destruction, or over-hunting. All of these factors can contribute to the deaths of various animals which ultimately leads to extinction if left unchecked.

Explanation:

8 0
3 years ago
A vehicle starts from rest and accelerates uniformly for 12 seconds to a
xz_007 [3.2K]

The value of the acceleration is 0.76 m/s² and the total time taken by the vehicle is 39 seconds.

<h3>Acceleration of the vehicle</h3>

The acceleration of the vehicle before coming to rest is calculated as follows;

v² = u² + 2as

where;

  • v is the final velocity
  • u is the initial velocity
  • a is the acceleration
  • s is the distance traveled before stopping

the car came to rest with constant velocity attained after 12 seconds.

the initial velocity of the car before 12 seconds is zero.

v² = 0 + 2as

a = v²/2s

a = (10²)/(2 x 66)

a = 0.76 m/s²

<h3>Time of motion of the vehicle</h3>

d = ut + ¹/₂at²

where;

  • d is the total distance traveled
  • t is the time of motion
  • a is acceleration
  • u is initial velocity of the vehicle

580 = 0 + ¹/₂(0.76)t²

580 = 0.38t²

t² = 580/0.38

t² = 1,526.3

t = √1,526.3

t = 39 seconds

Thus, the value of the acceleration is 0.76 m/s² and the total time taken by the vehicle is 39 seconds.

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

5 0
2 years ago
Which quantum numbers must be the same for the orbitals that they designate to be degenerate in a many-electron system?
stealth61 [152]
<span>For the orbitals that designate to be degenerate in a many-electron system, the following quantum numbers should be equal:
1- principle quantum number (n) : this describes the most probable distance of the electron from the nucleus
2- o</span><span>rbital angular momentum quantum number (l) : this determines the shape of the orbital </span>
8 0
3 years ago
A 58 kg skier is going down a 35 degree slope. The areaof each
maxonik [38]

To solve this problem we will use a free body diagram that allows us to determine the Normal Force.

In general, the normal force would be equivalent to

N = mgcos\theta

Since the skier is standing on two skis, his weight will be divide by two

N' = \frac{mgcos\theta}{2}

Pressure is given as the force applied in a given area, that is

P = \frac{F}{A}

Replacing F with N'

P = \frac{N'}{A}

P = \frac{\frac{mgcos\theta}{2}}{A}

Our values are given as,

m = 58kg

g = 9.8m/s^2

\theta = 35\°

A = 0.3m^2

Replacing we have that

P = \frac{\frac{(58)(9.8)cos(35)}{2}}{0.3}

P = 776.01Pa

Therefore the pressure exerted by each ski on the snow is 776.01Pa

6 0
3 years ago
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