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Ostrovityanka [42]
3 years ago
7

Which factors affect heat transfer between a warm and a cool substance?

Physics
1 answer:
andrey2020 [161]3 years ago
5 0

Answer: B

Explanation:

It's not the time it took to heat the substance, so that rules out A and C.

This means that we only have to choose between

B. the area of contact

D. the area of the substances

(since everything else in each of those answers are the same)

Area of contact matters more (e.g. an object with greater surface area is exposed to the air more, will lose/gain heat quicker than an object with less surface area).

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Tina and her puppy are tugging on a rope each pulling on opposite ends when is tina doing work ? When is Tina doing work ?
Varvara68 [4.7K]

Explanation : Tina is doing work all of the time because whiles she’s pulling and allowing the rope to be pulled her body using muscles to keep herself upright and a firm grip on the rope.

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3 years ago
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A man is using a fishing rod to catch fish in figure 1.
ryzh [129]

Answer:

Explanation:

Remark

In general, these 3rd class levers are very inefficient. Because the force distance is smaller than the load distance, you need to pull upward with more force that the weight of the load. So whatever the load is, the force is going to be much greater.

The distances are always measured to the pivot unless you are asked something specific otherwise.

Givens

F = ?

weight = 6N

Force Distance = F*d = 0.5 m

Weight Distance =W*d1 = 2 m

Formula

F*Fd = W*Wd

Solution

F*0.5 = 6 * 2            Divide by 0.5

F = 12/0.5

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2 years ago
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6 0
3 years ago
Hi please may someone help me especially on the sketch part.
vaieri [72.5K]

Ignoring the air resistance it will take about 3 seconds for the object to reach the ground.We know that the acceleration due to gravity is 10m/s2.

We also know that the final velocity is 30 m/s while the initial velocity is 0 m/s

we can use the formulae for acceleration to calculate the time taken/

(final - initial velocity)/timetaken=10

(30-0)/timetaken=10

timetaken =30/10=3 seconds

7 0
3 years ago
A key falls from a bridge that is 45 m above the water. the key falls straight down and lands in a model boat traveling at a con
erastova [34]

Let the key is free falling, therefore from equation of motion

h = ut +\frac{1}{2}gt^2..

Take initial velocity, u=0, so

h = 0\times t + \frac{1}{2}g t^2= \frac{1}{2}gt^2.

h = 0\times t + \frac{1}{2}g t^2= \frac{1}{2}gt^2 \\\ t =\sqrt{\frac{2h}{g} }

As velocity moves with constant velocity of 3.5 m/s, therefore we can use formula

d= v \times t

From above substituting t,

d = v \times \sqrt{\frac{2h}{g} }.

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Thus, the distance the boat was from the point of impact when the key was released is 10.60 m.

7 0
3 years ago
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