D. When Alan's puck is moving at 21 m/s south, it collides

Amy walks 32 m right and then 12 m left. She turns and walks another 28 m right and then turns and walks 7 m left. What is Amy's

Karo-lina-s [1.5K]

Her displacement is 41m. First, she walks 32m to the right, then 12m to the left. I subtract 12 from 32 to get 20m. She walks 28m to the right. Add 28 to 20 and you get 48. Finally, she walks 7m to the left. Subtract 7, then you get 41m.

4 0

4 years ago

1) what is the difference between a question and hypothesis<br><br>

Agata [3.3K]

<h3>a research question does not simply state the purpose of the research;</h3><h3 /><h3> it also tells the audience the type of methodology the researcher adopts in finding answers.</h3><h3 /><h3> If a researcher suggests a relationship between two or more variables in a provisional statement, it is referred to as a hypothesis</h3>

{tex}7 \frac{1}{9} {/tex}

yes you the best

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7 0

3 years ago

A proton is 0.9 meters away from a 1.4 C charge. What is the magnitude of the electric force between the proton and the charge

Digiron [165]

Answer:

F = 2.49 x 10⁻⁹ N

Explanation:

The electrostatic force between two charged bodies is given by Colomb's Law:

$F = \frac{kq_1q_2}{r^2}\\$

where,

F = Electrostatic Force = ?

k = colomb's constant = 9 x 10⁹ N.m²/C²

q₁ = charge on proton = 1.6 x 10⁻¹⁹ C

q₂ = second charge = 1.4 C

r = distace between charges = 0.9 m

Therefore,

$F = \frac{(9\ x\ 10^9\ N.m^2/C^2)(1.6\ x\ 10^{-19}\ C)(1.4\ C)}{(0.9\ m)^2}$

8 0

3 years ago

Read 2 more answers

wo different electrical devices have the same power consumption, but one (device 1) is meant to be operated on 127 V AC and the

Ilya [14]

Answer:

a) R₂/R₁ = 0.3049

b) I₂ / I₁ = 1.81

c) (230)² / ( 127)² = 3.28

Explanation:

By definition the power consumption is:

P = I²*R ⇒ as I = V/R I² = (V/R)² and P = (V²/R²)*R

P = V²/R

P = power consumtion

I = current

R = is the resistor

Case Device 1 Voltage 127 (V)

P₁ = V₁² /R₁ P₁ = (127)²/ R₁

Case Device 2 Voltage 230 (V)

P₂ = ( 230)²/ R₂

As P₁ = P₂ (127)²/R₁ = (230)²/R₂

(127)²/(230)² = R₂/R₁

a) R₂/R₁ = 0.3049

b) P₁ = I₁²*R₁ P₂ = I₂²*R₂

I₂² *R₂ = I₁²*R₁

I₂² / I₁² = R₁/R₂

I₂² / I₁² = 1/ 0.3049

I₂² / I₁² = 3.2797

√ (I₂² / I₁² ) = √3.2797

b) I₂ / I₁ = 1.81

c) P₁ = V₁*I₁ ⇒ P₁ = V₁²/R₁ if we "use" the device in 230 (V)

P₁´ = V₂² / R₁

P₁ = (127)²/R₁ and P₁´ = (230)²/ R₁

Then the increasing factor is:

c) (230)² / ( 127)² = 3.28

5 0

3 years ago

A spring of force constant k is compressed by a distance x from its equilibrium length. Does the mass of the spring change when

Sergio [31]

When the spring is compressed the energy is added to the spring. The energy in a compressed spring is more than in an uncompressed spring.

<h3>Spring Constant:</h3>

The required compression or tension (push or pull) that causes the spring to compress or expand to a specific distance is referred to as the spring constant in the context of mechanics. When a spring is compressed, work is added to the spring as more energy.

The energy is added to the spring when it is compressed. More energy is contained in compressed springs than in uncompressed springs.

One can compute the energy of spring as follows:

E = mc²

Here, the constant speed of light, c, and the spring's mass, m, is used.

Therefore, since the energy of the compressed spring is higher than the energy of the non-compressed spring and because the mass of the compressed spring is greater than the mass of the non-compressed increases, the energy only depends on the mass of the spring.

As a result, when spring is squeezed, its mass changes.

Learn more about spring here:

brainly.com/question/12253978

#SPJ4

3 0

2 years ago