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2 years ago

D. When Alan's puck is moving at 21 m/s south, it collides

Physics

1 answer:

kirza4 [7]2 years ago

5 0

D is s s s s s ss s s s s

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A 4n force is applied to an object with a mass of 2kg what is the accelertion of the object

Pavel [41]

As per Newton's law we know that

F = ma

here we know that

F = 4 N

m = 2 kg

so from this equation we will have

4 = 2 a

a = 4/2 = 2 m/s^2

so the acceleration will be 2 m/s^2

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2 years ago

Two tiny particles having charges 20.0 μC and 8.00 μC are separated by a distance of 20.0 cm What are the magnitude and directio

Alecsey [184]

Answer:

The magnitude and direction of electric field midway between these two charges is $10.8\times10^{5}\ N/C$ along AB.

Explanation:

Given that,

First charge $q_{1}= 20\mu C$

second charge $q_{2}= 8\mu C$

Distance = 20 cm

We need to calculate the electric field

For first charge,

Using formula of electric field

$E_{1}= \dfrac{kq_{1}}{r^2}$

Put the valueinto the formula

$E_{1}=\dfrac{9\times10^{9}\times20\times10^{-6}}{10\times10^{-2}}$

$E_{1}=18\times10^{5}\ N/C$

Direction of electric field along AB

We need to calculate the electric field

For second charge,

Using formula of electric field

$E_{2}= \dfrac{kq_{2}}{r^2}$

Put the valueinto the formula

$E_{2}=\dfrac{9\times10^{9}\times8\times10^{-6}}{10\times10^{-2}}$

$E_{2}=7.2\times10^{5}\ N/C$

Direction of electric field along AO

We need to calculate the net electric field at midpoint

$E_{net}=E_{1}-E_{2}$

$E_{net}=(18-7.2)\times10^{5}\ N/C$

$E_{net}=10.8\times10^{5}\ N/C$

Direction of net electric field along AB

Hence, The magnitude and direction of electric field midway between these two charges is $10.8\times10^{5}\ N/C$ along AB.

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2 years ago

The result of a wave generator traveling faster than the speed of a wave is:

Vesnalui [34]

The result of a wave generator traveling faster than the speed of a wave is called as a boom. If the wave is a sound wave, it is called a sonic boom. However, if the wave is light, it is called as a luminal boom. Luminal bloom happens in some industries and is commonly called as the Cherenkov radiation.

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2 years ago

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When the moon is waxing, it's lighted part appears

kvv77 [185]

To increase it's size

Waxing is the opposite of waning, which is to decrease.

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3 years ago

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