Answer:
5 sqrt(10) = c
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2
9^2 + 13^2 = c^2
81 + 169 = c^2
250 = c^2
Take the square root of each side
sqrt(250) = c
sqrt(25) sqrt(10) = c
5 sqrt(10) = c
To solve problem 19, we must remember the order of operations. PEMDAS tells us that we should simplify numbers in parentheses first, exponents next, multiplication and division after that, and finally addition and subtraction. Using this knowledge, we can begin to simplify the problem by working out the innermost set of parentheses:
36 / [10 - (3-1)²]
36 / [10 - (2)²]
Next, we should still simplify what is inside the parentheses but continue to solve the exponents (the next letter in PEMDAS).
36/ (10-4)
After that, we should compute the subtraction that is inside the parentheses.
36/6
Finally, we can solve using division.
6
Now, we can move onto problem 20:
1/4(16d - 24)
To solve this problem, we need to use the distributive property, which allows us to distribute the coefficient of 1/4 through the parentheses by multiplying each term by 1/4.
1/4 (16d-24)
1/4(16d) - 1/4(24)
Next, we can simplify further by using multiplication.
4d - 6
Therefore, your answer to problem 19 is 6 and the answer to problem 20 is 4d -6.
Hope this helps!
Answer:
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Step-by-step explanation:
Let
x ----> the original length pf the piece of metal
y ----> the original width pf the piece of metal
we know that
----> equation A
The volume of the box is equal to
we have
substitute in the formula of volume
----> equation B
substitute equation A in equation B
solve for y
Solve the quadratic equation by graphing
using a graphing tool
The solution is y=21
Find the value of x
therefore
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Answer:
where is part b? Part A is 4/13
Step-by-step explanation:
this is because in total there are 13 marbles. and when you pull out a marble. 4 of them can be red. you can simplify that fraction if need be.
