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Serhud [2]
4 years ago
3

In a right triangle, if ∠θ=45° and the side opposite to this angle is 5√2 meters, what is the approximate length of the hypotenu

se?
Mathematics
2 answers:
Scilla [17]4 years ago
7 0
Sine 45 degrees = opp / hyp
hypotenuse = 5*sqrt(2) / sine(45)
hypotenuse = 5*sqrt(2) /.70711
hypotenuse = <span> <span> <span> 9.9999544793 </span> </span> </span>
hypotenuse is 10.


Pachacha [2.7K]4 years ago
5 0

Answer:

<h2>The hypothenuse is 10 meters long.</h2>

Step-by-step explanation:

We know by defintion that a right triangle has a righ angle which is equal to 90°.

So, by given, we know that one of the acute angles is 45°, that means the other acute angle is also 45°, because all three internal angles must sum 180°.

Now, the given angle is

\theta =45\°

And its opposite side is 5\sqrt{2}.

To find the hypothenuse we need to use the sin function, which relates the angle with its opposite side and the hypothenuse.

sin \theta =\frac{opposite}{hypothenuse}\\ sin 45\°=\frac{5\sqrt{2} }{h}

Now, we solve for h

h=\frac{5\sqrt{2} }{sin45\°}\\ h=\frac{5\sqrt{2} }{\frac{\sqrt{2} }{2} } \\h=\frac{10\sqrt{2} }{\sqrt{2} }\\ h=10

Thereofre, the hypothenuse is 10 meters long.

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