Answer:
19 and below because a whole number is just a number that isn't a fraction. They are basic counting numbers
Explanation:
<h2>A is the correct answer!</h2><h3></h3><h3>I'm too lazy to explain :(</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
Answer:
The tension force has a magnitude of 490 N, and acts vertically upward
Explanation:
The complete question is:
A 50kg chandelier hangs from a ceiling suspended by a cable. What is the Tension (magnitude and direction of the force) in the cable?
ANS:
Tension is the force applied axially by rope, chain, cable, rod, etc, as a reaction force. The direction of tension is always towards the support. Since, the support here, is ceiling.
Therefore, the direction of tension force will be <u>vertically upward</u><u>.</u>
Since the chandelier is hanging stationary, without any motion. Thus, there must not be any unbalanced force applied on it.
Hence, the tension force must be equal to the weight of chandelier.
Tension Force = Weight of Chandelier
T = W = mg
T = (50 kg)(9.8 m/s²)
<u>T = 490 N</u>
<u>Thus, the tension force has a magnitude of 490 N, and acts vertically upward</u>
Answer:
T2=336K
Explanation:
Clausius-Clapeyron equation is used to determine the vapour pressure at different temperatures:
where:
In(P2/P1) = ΔvapH/R(1/T1 - 1/T2)
p1 and p2 are the vapour pressures at temperatures
T1 and T2
ΔvapH = the enthalpy of vaporization of the liquid
R = the Universal Gas Constant
p1=p1, T1=307K
p2=3.50p1; T2=?
ΔvapH=37.51kJ/mol=37510J/mol
R=8.314J.K^-1moL^-1
In(3.50P1/P1)= (37510J/mol)/(8.314J.K^-1)*(1/307 - 1/T2)
P1 and P1 cancelled out:
In(3.50)=4511.667(T2 - 307/307T2)
1.253=14.696(T2 - 307/T2)
1.253=(14.696T2) - (14.696*307)/T2
1.253T2=14.696T2 - 4511.672
Therefore,
4511.672=14.696T2 - 1.253T2
4511.672=13.443T2
So therefore, T2=4511.672/13.443=335.61
Approximately, T2=336K
