All categories

3 years ago

When the core of a star like the sun uses up its supply of hydrogen for fusion, the core begins to ________?

2 answers:

4 0

When the core of a star like the sun uses up its supply of hydrogen for fusion, the core begins to contract in size. The gravitational forces becomes strong and cause the star to reduce in size. as the star contracts, the temperature of the star also rises since the heat is distributed inside smaller Volume now.

Marrrta [24]3 years ago

3 0

Its core contracts, but its outer layers expand and the star becomes bigger and brighter.

You might be interested in

Let's say you go on a run and start to sweat because you are heating up.

Jobisdone [24]

Answer:

kinetic to thermal

Explanation:

4 0

3 years ago

Two identical asteroids travel side by side while touching one another. If the asteroids are composed of homogeneous pure iron a

victus00 [196]

Answer:

diameter = 21.81 ft

Explanation:

The gravitational force equation is:

$F=\frac{GMm}{R^{2} }$

Where:

F => Gravitational force or force of attraction between two masses
M => Mass of asteroid 1
m => Mass of asteroid 2
R => Distance between asteroids 1 and 2 (from center of gravity)

We also know that the asteroids are identical so their masses are identical:

Since R is the distance between centers of the two asteroids and their diameters are identical (see attachment), we can conclude that:

R=d=2r

We don´t know the mass of the asteroids but we know they are composed of pure iron, so we can relate their masses to their density:

m=ρV

This is going to be helpful because the volume of a sphere is:

$\frac{4}{3}\pi r^{3}$

And know we can write our original force of gravity equation in terms of the radius of the asteroids:

$F=\frac{GMm}{R^{2} } =\frac{Gmm}{(2r)^{2} } =\frac{Gm^{2} }{4r^{2} }$
$F=\frac{G ( \frac{4}{3}\pi r^{3}ρ)^{2} }{4r^{2} }$
$F= \frac{G(16)\pi ^{2} r^{6} ρ^{2}}{(9)(4)r^{2} } =\frac{G(16)\pi ^{2} r^{4}ρ^{2} }{36}$

Now let´s plug in the values we know:

$F = 1 lb$ mutual gravitational attraction force
$G = 6.67(10)^{-11}$ gravitational constant
$ρ_{iron} =491.5 \frac{lb}{ft^{3} }$

$1= \frac{6.67(10)^{-11} \pi ^{2} r^{4} (491.5)^{2}}{36}$

Solve for r and multiply by 2 because 2r = diameter

$d=2\sqrt[4]{\frac{1}{7.07(10)^{-5} } }$

Result is d = 21.81 Feet

6 0

2 years ago

A current carrying wire is surrounded by a magnetic field. True or false

Aleks04 [339]

The answer is true because A current carrying wire is surrounded by magnetic field

7 0

3 years ago

H. Briefly describe the process taking place in the image below and comment on the

katrin [286]

AHEMHFgjrhfrshfghesgrgregr

3 0

2 years ago

Keisha analyzes this circuit diagram.

Mazyrski [523]

Component ' W ' is the standard schematic symbol for a switch.

The short line between the two circles can be shown straight,
like it is now, when the switch is 'closed' and current can flow.

Or, it can also be drawn slightly tilted, so it's not touching one
of the circles. In that case, the switch is 'open', no current can
flow through it, and the whole circuit is shut down.

9 0

3 years ago

Read 2 more answers