This should help here you go
Answer:adsfsaffkfhsadfs
Step-by-step explanation:
I need point sorry im doing a compeition
Answer:
AKPOS/ACGF = 28√3 -48 ≈ 0.497423
Step-by-step explanation:
Let's assume the square is a unit square. Then the height of the triangle is ...
1 +(√3)/2 = h
and half the base of the triangle is ...
h/√3 = (√3)/3 +1/2 = b/2
The area of the triangle is the product of these:
A = (1/2)bh
= (2 +√3)/2 × (3 +2√3)/6
= (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12
So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...
(square area)/(triangle area) = 12/(12+7√3)
(square area)/(triangle area) = 28√3 -48
First you have to make 7 a fraction, every fraction with the denominator 1 is a whole number, so 7 should be 7/1,
7/1×2/3
=14/3
=4 2/3
answer=4 2/3
hope this helps....
Answer:
6
Step-by-step explanation: You can set up the equation:
=
You square both sides to cancel out the squares which leaves you with
= n - 4. Then you just solve as normal which ends you up with an answer of 6. You can check this by plugging 6 back into the equation and see that you end up with
on both sides.