Given:
mass: 100 kg
height: 500 m
1 kJ = 1000 J
gravity = 9.8 m/s²
velocity before impact: v = √2gh ; v = √2 * 9.8 m/s² * 500 m ; v = 98.99494 m/s
KE = 1/2 m v²
KE = 1/2 * 100 kg * (98.99494 m/s)²
KE = 490,000 J
Pls. see attachment.
Hello!
![\large\boxed{F = 100N}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BF%20%3D%20100N%7D)
Use the equation F = m · a (Newton's Second Law) to solve. Substitute in the given values:
F = 5 · 20
F = 100N
A. Molecular solids tend to have lower melting points than Ionic so it would be Ionic if it weren't for Molecular.
<h2>QUESTION:- </h2>
➜what is kepler's law??
![\huge\red{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W}\orange{ER}}}}](https://tex.z-dn.net/?f=%5Chuge%5Cred%7B%5Cboxed%7B%5Chuge%5Cmathbb%7B%5Cred%20A%20%5Cpink%7BN%7D%5Cpurple%7BS%7D%20%5Cblue%7BW%7D%5Corange%7BER%7D%7D%7D%7D)
Kepler gave the three laws or theorems of motion of the orbitals bodies
![{\huge {\bold{ \red{ \star}}}}{ \blue{ \bold{FIRST \: \: \: LAW}}}](https://tex.z-dn.net/?f=%7B%5Chuge%20%7B%5Cbold%7B%20%5Cred%7B%20%5Cstar%7D%7D%7D%7D%7B%20%5Cblue%7B%20%5Cbold%7BFIRST%20%5C%3A%20%5C%3A%20%5C%3A%20LAW%7D%7D%7D)
This law state that the celestial bodies revolves around the stars in elliptical orbit and star as a single focus.
Example :- Earth revolves around the Sun as assuming it as single focus
This also shows that earth revolves around the sun in elliptical orbit.
![{\huge {\bold{ \blue{ \star}}}}{ \green{ \bold{SECOND \: \: \: LAW}}}](https://tex.z-dn.net/?f=%7B%5Chuge%20%7B%5Cbold%7B%20%5Cblue%7B%20%5Cstar%7D%7D%7D%7D%7B%20%5Cgreen%7B%20%5Cbold%7BSECOND%20%5C%3A%20%5C%3A%20%5C%3A%20LAW%7D%7D%7D)
Area covered by the planet is equal in equal duration of time irrespective of the position of the planet.
It also states that Angular momentum is constant
As Angular momentum is constant it means areal velocity is also constant.
![\frac{ \triangle \: A}{ \triangle \: T} = \frac{L}{2m}△T△A=2mL](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Ctriangle%20%5C%3A%20A%7D%7B%20%5Ctriangle%20%5C%3A%20T%7D%20%3D%20%5Cfrac%7BL%7D%7B2m%7D%E2%96%B3T%E2%96%B3A%3D2mL)
where:-
A is the area.
T is the time.
L is the angular momentum.
M is the mass of the body.
![{\huge {\bold{ \green{ \star}}}}{ \purple{ \bold{THIRD \: \: \: LAW}}}](https://tex.z-dn.net/?f=%7B%5Chuge%20%7B%5Cbold%7B%20%5Cgreen%7B%20%5Cstar%7D%7D%7D%7D%7B%20%5Cpurple%7B%20%5Cbold%7BTHIRD%20%5C%3A%20%5C%3A%20%5C%3A%20LAW%7D%7D%7D)
square of the time of the revolution is directly proportional to the cube of the distance between the planet and star in Astronomical unit.
![{T}^{2} = {a}^{3}T2=a3](https://tex.z-dn.net/?f=%7BT%7D%5E%7B2%7D%20%3D%20%7Ba%7D%5E%7B3%7DT2%3Da3)
where:-
T = time of revolution
a is the distance between the planet and star.
![\purple\star \: {Thanks \: And \: Brainlist} \blue \star \\ {\orange{ \star}}{if \: U \: Like d \: My \: Ans} {\green{ \star }}](https://tex.z-dn.net/?f=%5Cpurple%5Cstar%20%5C%3A%20%7BThanks%20%5C%3A%20And%20%5C%3A%20Brainlist%7D%20%5Cblue%20%5Cstar%20%5C%5C%20%7B%5Corange%7B%20%5Cstar%7D%7D%7Bif%20%5C%3A%20U%20%5C%3A%20Like%20d%20%5C%3A%20My%20%5C%3A%20Ans%7D%20%7B%5Cgreen%7B%20%5Cstar%20%7D%7D)
Answer:120 min
Explanation:
Given
Amanda spent
of her time after school doing Home work
And
of her remaining time riding her bike
It is given that she rode her bike for 45 minutes in a week
Let t be the time after school
therefore Amanda spend
in home work and
time is left
From remaining
time she spends
time riding her bike
therefore ![\frac{3t}{5}\times \frac{1}{4}=45](https://tex.z-dn.net/?f=%5Cfrac%7B3t%7D%7B5%7D%5Ctimes%20%5Cfrac%7B1%7D%7B4%7D%3D45)
thus ![t=300 min](https://tex.z-dn.net/?f=t%3D300%20min)
therefore time spent on home work is ![\frac{2}{5}\times 300=120 min](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%5Ctimes%20300%3D120%20min)