4 years ago

Which forms first: protoplanets or planetesimals?

1 answer:

6 0

A planetesimal is small bodies from which a planet originated in the early stages of formation of the solar system. Protoplanets are when planetesimals join together through collisions and through the force of gravity to form larger bodies.

Therefore, planetesimals are formed first.

You might be interested in

There are usually _________ collisions in a motor vehicle crash.

mel-nik [20]

Answer:

Explanation:

During a crash 3 types of collisions can occur.

5 0

3 years ago

A circuit has a resistance of 8 Ohms. the voltage supplied to the circuit is 14 volts. what is the current flowing through it?

valina [46]

Answer:

e jiio7ruetw5258o0pomnmitwq2690okm ,,kkkiiht44456

3 0

3 years ago

Which statement is TRUE about the factors affecting physical fitness?A.

seropon [69]

Answer:

Explanation:

6 0

3 years ago

A 1200-kg station wagon is moving along a straight highway at Another car, with mass 1800 kg and speed has its center of mass 40

taurus [48]

Answer:

Center of mass lies 24 m in front of center of mass of second wagon.

Explanation:

Suppose A 1200 kg station wagon is moving along a straight highway at 12.0 m/s. Another car with mass 1800 kg and speed 20.0 m/s.

Given that,

Mass of first wagon = 1200 kg

Mass of second wagon = 180 kg

Distance = 40 m

We need to calculate the position of the center of mass of the system

Using formula of center mass

$x_{cm}=\dfrac{m_{1}x_{1}+m_{2}x_{2}}{m_{1}+m_{2}}$

$x_{cm}=\dfrac{1200\times0+1800\times40}{1200+1800}$

$x_{cm}=24\ m$

Hence, Center of mass lies 24 m in front of center of mass of second wagon.

5 0

3 years ago

A frog falls from its rainforest tree. If we ignore wind resistance, (a) how much time does it take the frog to fall a distance

gtnhenbr [62]

Answer:

Explanation:

a) Using the equation of motion

S = ut + 1/2gt²

S is the distance of fall

g is the acceleration due to gravity

t is the time taken

Given S = 12.0m, g = 9.81m/s^2, un= 0m/s

12 = 0+1/2(9.81)t²

12 = 4.905t²²²

t² = 12/4.905

t² = 2.446

t = √2.446

t = 1.56secs

b) To determine how fast is the frog falling at this point, we need to calculate the speed of the frog. Using the equaton v = u+gt

v = 0+9.81(1.56)

v = 15.34m/s

Hence the frog is falling at the rate of 15.34m/s

5 0

3 years ago