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Veseljchak [2.6K]
2 years ago
15

Assume a current of 1 ampere enters a parallel circuit at Point A. This 1 ampere of current will ________________ between Resist

ors R1 and R2 and then recombine at Point B
Physics
1 answer:
kow [346]2 years ago
5 0

If a current of 1 ampere enters a parallel circuit at Point A. This 1 ampere of current will divide between Resistors R1 and R2 and then recombine at Point B

<h3>Parallel circuit</h3>

A  parallel circuit is a circuit with separate branches with a common endpoint. In a parallel circuit, the voltage across each branch is the same but the currents vary. The total current is the sum of the currents flowing through each component.

If a current of 1 ampere enters a parallel circuit at Point A. This 1 ampere of current will divide between Resistors R1 and R2 and then recombine at Point B.

Find out more on Parallel circuit at: brainly.com/question/80537

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Two taut strings of identical mass and length are stretched with their ends fixed, but the tension in one string is 1.10 times g
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Answer:

The  beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz

Explanation:

Given;

velocity of wave on the string with lower tension, v₁ = 35.2 m/s

the fundamental frequency of the string, F₁ = 258 Hz

<u>velocity of wave on the string with greater tension;</u>

v_1 = \sqrt{\frac{T_1}{\mu }

where;

v₁ is the velocity of wave on the string with lower tension

T₁ is tension on the string

μ is mass per unit length

v_1 = \sqrt{\frac{T_1}{\mu} } \\\\v_1^2 = \frac{T_1}{\mu} \\\\\mu = \frac{T_1}{v_1^2} \\\\ \frac{T_1}{v_1^2} =  \frac{T_2}{v_2^2}\\\\v_2^2 = \frac{T_2v_1^2}{T_1}

Where;

T₁ lower tension

T₂ greater tension

v₁ velocity of wave in string with lower tension

v₂ velocity of wave in string with greater tension

From the given question;

T₂ = 1.1 T₁

v_2^2 = \frac{T_2v_1^2}{T_1}  \\\\v_2 = \sqrt{\frac{T_2v_1^2}{T_1}} \\\\v_2 = \sqrt{\frac{1.1T_1*(35.2)^2}{T_1}}\\\\v_2 = \sqrt{1.1(35.2)^2} = 36.92 \ m/s

<u>Fundamental frequency of wave on the string with greater tension;</u>

<u />f = \frac{v}{2l} \\\\2l = \frac{v}{f} \\\\thus, \frac{v_1}{f_1}  =\frac{v_2}{f_2} \\\\f_2 = \frac{f_1v_2}{v_1} \\\\f_2 =\frac{258*36.92}{35.2} \\\\f_2 = 270.6 \ Hz<u />

Beat frequency = F₂ - F₁

                          = 270.6 - 258

                          = 12.6 Hz

Therefore, the  beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz

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