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Olin [163]
3 years ago
9

A man whose mass is 90 kg is 6.38x106m away from the center of the earth. If the Earth’s mass is6x1024kgand the constant Gis 6.6

7x10-11what is the force of gravity on the man

Physics
2 answers:
inysia [295]3 years ago
8 0

Answer: force of gravity is 885N

Explanation:

Jobisdone [24]3 years ago
4 0

Answer:1N

Explanation:

Mass1(m1)=90kg

Mass2(m2)=6x10^24kg

Gravitational constant(G)=6.67x10^(-11)

Distance apart(d)=6.38x10^6m

Force of gravity(f)=?

F=(Gxm1xm2)/d^2

F=(6.67x10^(-11)x90x6x10^24)/(6.38x10^6)

F=(3.6018x10^16)/(6.38x10^6)

F=1N

Force of gravity=1N

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7 0
3 years ago
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Gasoline flows in a long, underground pipeline at a constant temperature of 15o C (rho = 680 kg/m3 ; ν = 4.6 × 10-7 m2 /s). Two
poizon [28]

Answer:

1.0416 m∧3/sec

Explanation:

check the pictures below for the solution

8 0
3 years ago
2. You will need a magnifying glass and a small piece of scrap paper for this demonstration. a. Go outside on a sunny day and pu
andrew-mc [135]

The focal length of a magnifying glass is the distance between the focal point and optical centre of the magnifying glass.

<h3>Focal length</h3>

The focal length, f is the distance from a lens or mirror to the focal point, F.

This is the distance from a lens or mirror at which parallel light rays will meet for a converging lens or mirror or appear to diverge from for a diverging lens or mirror.

A magnifying glass is a converging lens which produces a enlarged, erect and virtual image when an object is placed between the focal point and optical centre.

A magnifying glass will bring to focus at a point sun rays which can cause the paper to catch fire if it is held in place for long.

This point at which the most concentrated ray of light is shining on the paper, is the focal point for that magnifying glass.

Therefore, the focal length of a magnifying glass is the distance between the focal point and optical centre of the magnifying glass.

Learn more about about focal length at: brainly.com/question/25779311

4 0
2 years ago
A cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains air
Ganezh [65]

Answer:

0.435atm

Explanation:

cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains air with a volume of 0.185 m3 at a pressure of 0.740 atm. The piston is slowly pulled out until the volume of the gas is increased to 0.315 m3. If the temperature remains constant, what is the final value of the pressure?

Given

Initial pressure P1= 0.740atm

Initial volume V1= 0.185 m3

Final pressure P2= ?

Final volume V2= 0.315 m3

At constant temperature, the pressure of a syste is inversely proportional to volume, by Boyles law then

P1V1=P2V2

P2=P1V1/V2

=(0.185*0.740)/0.315

0.1369/0.315

= 0.435atm

Therefore, final pressure is 0.435atm

7 0
2 years ago
A body accelerates uniformly from rest at 2ms² for 5 seconds . calculate its average velocity in this time.​
timama [110]

Answer:

0.4

Explanation:

average velocity =d/t

2/5=0.4

0.4m

7 0
3 years ago
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