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Olin [163]
3 years ago
9

A man whose mass is 90 kg is 6.38x106m away from the center of the earth. If the Earth’s mass is6x1024kgand the constant Gis 6.6

7x10-11what is the force of gravity on the man

Physics
2 answers:
inysia [295]3 years ago
8 0

Answer: force of gravity is 885N

Explanation:

Jobisdone [24]3 years ago
4 0

Answer:1N

Explanation:

Mass1(m1)=90kg

Mass2(m2)=6x10^24kg

Gravitational constant(G)=6.67x10^(-11)

Distance apart(d)=6.38x10^6m

Force of gravity(f)=?

F=(Gxm1xm2)/d^2

F=(6.67x10^(-11)x90x6x10^24)/(6.38x10^6)

F=(3.6018x10^16)/(6.38x10^6)

F=1N

Force of gravity=1N

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The sputnik one satellite orbiting earth mass equals 5.98×10 to the 24th power kilograms in a circle of radius 6.96×10 to the si
nika2105 [10]

Answer:

7572 m/s

Explanation:

The force between two masses separated by a distance r is given as:

F=G\frac{m_1m_2}{r^2}

Where F is the attractive force between 2 masses, m1 and m2, r is the distance between the centres of the masses and G is the universal gravitation constant, which is 6.674*10^-11 Nm^2/kg^2

The mass of the earth (m_1) is far greater than the mass of the sputnik (m_2). Therefore m_1m_2=m_1. The mass of the sputnik is neglected, therefore:

F=G\frac{m_1}{r^2}=\frac{(6.674*10^{-11})(5.98*10^{24})}{(6.96*10^6)^2} = 8.2389N

But F is actually centripetal acceleration, a = v²/r

8.2389 = v^2 / 6.96*10^6\\v=7572m/s

6 0
3 years ago
Two 5000-kg passenger cars roll without friction (one at 1 m/s, the other at 2 m/s) toward one another on a level track. They co
balu736 [363]

The combined momentum of the passengers is 5000 kgm/s.

<h3>Combined momentum of the passenger</h3>

The combined momentum of the passengers is calculated as follows;

P = mv1 + mv2

where;

  • m is mass of the passengers
  • v1 is velocity of the first passenger
  • v2 is velocity of the second passenger

P = m(v1 + v2)

P = 5000(-1 + 2)

P = 5000 kgm/s

Thus, the combined momentum of the passengers is 5000 kgm/s.

Learn more about momentum here: brainly.com/question/7538238

#SPJ1

5 0
2 years ago
a wheel 0.35m in diameter rotates at 2200rpm. calculate its angular velocity in rad/s and its linear speed and acceleration of a
bazaltina [42]

Answer:

( Angular Velocity = ( About ) 230 rad / s,

( Linear Speed = ( About ) 40.25 m / s,

( Acceleration = ( About ) 9290 m / s^2

Explanation:

Here we want the angular velocity in radians per second, the linear velocity and acceleration.

The diameter = .35 meters, and thus we can conclude that the radius be half of that, or .175 meters. For part ( a ), or the calculation of the angular velocity, it is given that the diameter rotates at 2200 revolutions per minute - but we need to convert this into radians per second.

We can say that there are 2π radians for every minute, and for every minute there are 60 seconds. Therefore -

( a ) w = 2,200 rpm( 2π rads / rev )( 1 min / 60 sec )...

Hence, w = ( About ) 230 rad / s

_____

For this second part we can calculate the the linear velocity by multiplying the angular velocity ( omega ) by the radius r -

( b ) v = w( r ) - Substitute,

v = ( 230 rad / sec )( .175 m )...

v = ( About ) 40.25 m / s

_____

And for this last bit here, to find the acceleration we can simply take the angular velocity ( omega ) squared, by the radius r -

( c ) a_{rad} = w^2( r ),

a_{rad} = ( ( 230 rad / sec )^2 )( .175 m )...

a_{rad} = ( About ) 9290 m / s^2

7 0
3 years ago
In the design of a supermarket, there are to be several ramps connecting different parts of the store. Customers will have to pu
tatuchka [14]

Answer:

3.90 degrees

Explanation:

Let g= 9.81 m/s2. The gravity of the 30kg grocery cart is

W = mg = 30*9.81 = 294.3 N

This gravity is split into 2 components on the ramp, 1 parallel and the other perpendicular to the ramp.

We can calculate the parallel one since it's the one that affects the force required to push up

F = WsinΘ

Since customer would not complain if the force is no more than 20N

F = 20

294.3sin\theta = 20

sin\theta = 20/294.3 = 0.068

\theta = sin^{-1}0.068 = 0.068 rad = 0.068*180/\pi \approx 3.90^0

So the ramp cannot be larger than 3.9 degrees

6 0
3 years ago
What role does voltage play in the formation or use of an electromagnet?
Dafna11 [192]
<span>Voltage overcomes the resistance of the electromagnet winding to force a current through that resistance. The field strength is proportional to the coil current. More voltage pushes more current. More voltage builds up the current faster, as well as forcing it to a higher final value. </span>
3 0
2 years ago
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