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arlik [135]
3 years ago
11

What is kinetic energy and what is net force formula

Physics
1 answer:
Over [174]3 years ago
6 0

Answer:

Here's the equation for net force: F = ma. The work done on the plane, which becomes its kinetic energy, equals the following: Net force F equals mass times acceleration. Assume that you're pushing in the same direction that the plane is going; in this case, cos 0 degrees = 1, so.

Explanation:

In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes

Hope this help also looking it up helps ;)

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A 20 newton force moves an object southeast. What two properties of force have been described?
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Answer:

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Explanation:

Force is a vector quantity so it has both magnitude and direction. The question shows 20N act as magnitude and Southeast act as direction.

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The electric field 14.0 cm from the surface of a copper ball of radius 2.0 cm is directed toward the ball's center and has magni
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Q = - 256 X 10⁻⁷ C .

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Electric field due to a charge Q at a distance d from the center is given by the expression

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A (10.0+A) g ice cube at -15.0oC is placed in (125 B) g of water at 48.0oC. Find the final temperature of the system when equili
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Answer: Final temperature is 34.15°C.

Explanation: When two objects have different temperature, they will exchange heat energy until there is no more net energy transfer between them. At that state, the objects are in <u>thermal</u> <u>equilibrium</u>.

So, when in equilibrium, the total heat flow must be zero, i.e.:

Q_{1}+Q_{2}=0

In our case, there will be a change in state of ice into water, so total heat flow will be:

m_{1}c_{1}(T_{f}-T_{i})+m_{2}c_{2}(T_{f}-T_{i})+mL=0

where

m₁ is mass of ice

m₂ is mass of water

c₁ is specific heat of ice

c₂ is specific heat of water

T_{f} is final temperature

T_{i} is initial temperature

L is latent heat fusion

Temperature is in Kelvin so the transformation from Celsius to Kelvin:

For ice:

T = -15 + 273 = 258K

For water:

T = 48 + 273 = 321K

Solving:

21(2.09)(T_{f}-258)+158(4.186)(T_{f}-321)+21(333)=0

43.89T_{f}-11323.62+661.4T_{f}-212305.55+6993=0

705.3T_{f}=216636.17

T_{f}= 307.15K

In Celsius:

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Final temperature of the system when in equilibrium is 34.15°C

4 0
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