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serg [7]
3 years ago
12

If 5.0 liters of carbon dioxide gas are produced by the reaction below at STP, how many liters of oxygen gas were used in the re

action?
2CO (g) + O2 (g) 2CO2 (g)
10.0 L
7.5 L
5.0 L
2.5 L
Chemistry
1 answer:
svp [43]3 years ago
4 0
At STP

1L O₂ → 2L CO₂
xL O₂ → 5.0L CO₂

x=2.5 L
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How many molecules are in 85 grams of Silver?
densk [106]

Answer:

3.0 × 10

3.0 \times  {10}^{23}

molecules

Explanation:

there are many molecules

8 0
3 years ago
A student mixes a solution containing 10.0 g bacl2 (m = 208.2) with a solution containing 10.0 g na2so4 (m = 142.1) and obtains
professor190 [17]
The balanced equation for the above reaction is as follows;
Na₂SO₄ + BaCl₂ --> BaSO₄ + 2NaCl
Na₂SO₄ reacts with BaCl₂ in the molar ratio 1:1
Number of Na₂SO₄ moles - 10.0 g / 142.1 g/mol = 0.0704 mol
Number of BaCl₂ moles - 10.0 g / 208.2 g/mol = 0.0480 mol
this means that 0.0480 mol of each reactant is used up, BaCl₂ is the limiting reactant and Na₂SO₄ has been provided in excess. 
stoichiometry of BaCl₂ to BaSO₄ is 1:1
number of BaSO₄ moles formed - 0.0480 mol
Mass of BaSO₄ - 0.0480 mol x 233.2 g/mol = 11.2 g
theoretical yield is 11.2 g but the actual yield is 12.0 g
the actual product maybe more than the theoretical yield of the product as the measured mass of the actual yield might contain impurities. 
percent yield - 12.0 g/ 11.2 g x 100% = 107% 
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4 0
4 years ago
A student calculates the density of an unknown metal sample to be 8.25 g/cm3
romanna [79]

Answer:

the answer is b

Explanation:

mass=198 divided by volume 24 gives you 8.25

4 0
3 years ago
Chemical compounds
V125BC [204]

Answer: can be made up of one atom with several different elements in it (b)

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7 0
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Using the mass of a proton 1.0073 amu and assuming it's diameter is1.0x10^-15, calculate the density of a proton in g/cm^3. I'm
valkas [14]
You just have to find a conversion from amu to grams. For every 1 amu, there is 1.66×10⁻²⁴ grams. Thus,

Mass of proton = 1.0073 amu * 1.66×10⁻²⁴ grams/amu = 1.672×10⁻²⁴ grams

Since a proton is spherical in shape, the volume would be:

Volume = 1/6*πd³ = 1/6*π(1.0×10⁻¹⁵ cm)³ = 5.236×10⁻⁴⁶ cm³

Therefore, the density is equal to

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Density = 3.2×10²¹ g/cm³
4 0
3 years ago
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