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serg [7]
3 years ago
12

If 5.0 liters of carbon dioxide gas are produced by the reaction below at STP, how many liters of oxygen gas were used in the re

action?
2CO (g) + O2 (g) 2CO2 (g)
10.0 L
7.5 L
5.0 L
2.5 L
Chemistry
1 answer:
svp [43]3 years ago
4 0
At STP

1L O₂ → 2L CO₂
xL O₂ → 5.0L CO₂

x=2.5 L
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How many moles are there in 8.50 X 1024 molecules of sodium sulfate, Na2SO3?
il63 [147K]

Answer:

<h2>14.12 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.50 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 14.119601...

We have the final answer as

<h3>14.12 moles</h3>

Hope this helps you

3 0
2 years ago
Be sure to answer all parts. Consider the following balanced redox reaction (do not include state of matter in your answers): 2C
timurjin [86]

Answer:

The specie which is oxidized is:- CrO_2^-

The specie which is reduced is:- ClO^-

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

For the given chemical reaction:

2CrO_2^- + 6ClO^- + 2H_2O\rightarrow 2CrO_4^{2-} + 3Cl_2 + 4OH^-

The half cell reactions for the above reaction follows:

Oxidation half reaction:  CrO_2^- + 2H_2O + 4OH^-\rightarrow CrO_4^{2-} + 4H_2O + 3e^-

Reduction half reaction:  2ClO^- + 4H_2O + 2e^-\rightarrow Cl_2 + 2H_2O + 4OH^-

Thus, the specie which is oxidized is:- CrO_2^-

The specie which is reduced is:- ClO^-

8 0
3 years ago
Speed is defined as __________.
MariettaO [177]

Answer:D)

Explanation: the distance traveled over time

6 0
2 years ago
At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressur
fenix001 [56]

At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the  partial pressure of He would give a solubility of 0.200 M.

<h3>What is Henry's Law ?</h3>

Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.

<h3>What is relationship between Henry's Law constant and Solubility ?</h3>

The solubility of gas is directly proportional to partial pressure.

It is expressed as:

S_{\text{gas}} = K_{H} P_{\text{gas}}

where,

S_{\text{gas}} = Solubility of gas

K_{H} = Henry's Law constant

P_{\text{gas}} = Partial pressure of gas

Now put the values in above expression we get

S_{\text{gas}} = K_{H} P_{\text{gas}}

0.080M = K_{H} × 1.7 atm

K_{H} = \frac{0.080\ M}{1.7\ \text{atm}}

      = 0.047 M/atm

Now we have to find the partial pressure of He

S_{\text{gas}} = K_{H} P_{\text{gas}}

0.200 M = 0.047 M/atm × P_{\text{gas}}

P_{\text{gas}} = \frac{0.200 M}{0.047\ \text{M/atm}}

       = 4.25 atm

Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the  partial pressure of He would give a solubility of 0.200 M.

Learn more about the Henry's Law here: brainly.com/question/23204201

#SPJ4

3 0
1 year ago
How many moles of HCl would react with 37.1 mL of 0.138 M Sr(OH)2
Lena [83]

Answer is: 0.102 moles of HCl would react.

Balanced chemical reaction:

2HCl(aq) + Sr(OH)₂ → SrCl₂(aq) + 2H₂O(l).

V(Sr(OH)₂) = 37.1 mL ÷ 1000 mL/L.

V(Sr(OH)₂) = 0.0371 L; volume of the strontium hydroxide solution.

c(Sr(OH)₂) = 0.138 M; molarity of the strontium hydroxide solution.

n(Sr(OH)₂) = c(Sr(OH)₂) · V(Sr(OH)₂).

n(Sr(OH)₂) = 0.0371 L · 0.138 mol/L.

n(Sr(OH)₂) = 0.0051 mol; amount of the strontium hydroxide.

From balanced chemical reaction: n(Sr(OH)₂) : n(HCl) = 1 : 2.

n(HCl) = 2 · n(Sr(OH)₂).

n(HCl) = 2 · 0.0051 mol.

n(HCl) = 0.0102 mol; amount of the hydrochloric acid.

5 0
3 years ago
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