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Cerrena [4.2K]
3 years ago
6

Calculation of NCl3

Chemistry
1 answer:
Aneli [31]3 years ago
8 0

Answer:

NCl3 = N2 + Cl2

Explanation:

I had this question before.

I hope I remembered it right!

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Describe how you mathematically convert the measured mass of a
RoseWind [281]

Answer:

no. of moles = measured mass of substance/ molar mass of the constituted elements

Explanation:

No. of moles of 2.0g NaCl= 2/(23+35.5) = 0.034mol

3 0
3 years ago
Identifying Wave Interactions<br> Which diagram (A or B) shows transmission?<br> Intro
Rama09 [41]

Answer:a

Explanation:

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4 0
4 years ago
How many atoms are in CaCl2​
MrRa [10]

There are three atoms in total! Hope this can help you out!

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3 years ago
If only 0.186 g of Ca(OH)2 dissolves in enough water to give 0.230 L of aqueous solution at a given temperature, what is the Ksp
Lilit [14]

Answer:

Ksp=5.20x10^{-6}

Explanation:

Hello there!

In this case, according to the solubility equilibrium of calcium hydroxide:

Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-

Whereas the equilibrium expression is:

Ksp=[Ca^{2+}][OH^-]^2

It is firstly necessary to calculate the molar solubility given the grams and volume of the dissolved solute:

s=\frac{0.186g/(74.09g/mol)}{0.230L}=0.0109M

Now, according to the Ksp expression, we plug in s as the solubility to obtain:

Ksp=(s)(2s)^2\\\\Ksp=(0.109)(2*0.0109)^2\\\\Ksp=5.20x10^{-6}

Regards!

8 0
3 years ago
What is the ratio of acetate ion to acetic acid (Ka = 1.76×10–5) in a solution containing these compounds at pH 4.38 ? Write you
jenyasd209 [6]

Answer:

0.43.

Explanation:

In order to solve this question we will need the an equation called Henderson-Hasselbalch Equation. The Henderson-Hasselbalch Equation can be represented by the reaction below;

pH= pKa + log ( [ A^- ] / [ HA] ).

Where HA is the acetic acid and A^- is the Acetate ion

We are given the pH value to be = 4.38 and the ka to be = 1.76×10^–5. So, we will use the value for the ka to find the pKa through the formula below.

pKa = - log ka.

Therefore, pKa = - log( 1.76×10^–5).

pKa= 4.75 + log

So,

4.38 = 4.75 + log ([ A^-] / [HA]).

4.38 - 4.75 = log ( [ A^- ] / [ HA] ).

( [ A^- ] / [ HA] ) = 10^- 0.37.

( [ A^- ] / [ HA] ) = 0.42657951880159265.

( [ A^- ] / [ HA] )= 0.43.

6 0
3 years ago
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