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antiseptic1488 [7]
3 years ago
15

Give one example of solution which exist in gas state?​

Chemistry
1 answer:
Lerok [7]3 years ago
6 0

Answer:

Air is one solution cant really explain why but it is

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A reaction mixture at 175 k initially contains 522 torr of no and 421 torr of o2. at equilibrium, the total pressure in the reac
zzz [600]
The chemical equation would be:

2NO(g) + O2(g) --> 2NO2 (g) 

<span>At equilibrium state, the partial pressure of the gases would be as follows : </span>

<span>NO = 522 - 2x </span>

<span>O2 = 421 - x </span>

<span>NO2 = 2x </span>
<span>- - - - - - - - - - - - -</span>
<span>943 - x = 748 </span>

<span>x = 195</span>

Calculating for Kp,

<span>Kp = (NO2)^2/ ((NO)^2 * (O2)) </span>

<span>Kp = (2 * 195)^2/ ((522 - 2 * 195)^2 * (421 - 195)) </span>

<span>Kp = 0.0386 </span>
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3 years ago
The half-life of an element is 200 years. If a 30 gram sample was originally deposited, how much is left after 200 years? Questi
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The gram that will be left is 15grams
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Write a scientific explanation that answers the following question: Is matter conserved during a
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Claim is : chemical reactions are smaller
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3. Although both wool and silk are poor conductors of heat. However, winter clothing is usually made using wool. Why​
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It’s made using wool because it compresses the coldest air there is and not get it to be trapped in the body

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In a similar experiment, a current of 2.15 amps ran for 8 minutes and 24 seconds. The temperature of the water was 26.0°C. The v
lord [1]

Answer:

\boxed{6.08 \times 10^{23}}

Explanation:

Data:

I = 2.15 A

t = 8 min 24 s

T = 26.0 °C

V = 65.4 mL

p = 774.2 To

1. Write the equation for the half-reaction

2H₂O ⟶ O₂ + 4H⁺ + 4e⁻

2. Calculate the moles of oxygen

p = \text{774.2 To} \times \dfrac{\text{1 atm}}{\text{760 To}} = \text{1.0187 atm}

V = 0.0654 L

T = (26.0 + 273.15) K = 299.15 K

\begin{array}{rcl}pV& = & nRT\\1.0189 \times 0.0654 & = & n \times 0.08206 \times 299.15\\0.06662 & = & 24.55n\\\\n & = & \dfrac{0.06662}{24.55}\\\\n & = & 2.714 \times 10^{-3}\\\end{array}

3. Calculate the moles of electrons

\text{n} = \text{2.714 $\times 10^{-3}$ mol oxygen} \times \dfrac{\text{4 mol electrons}}{\text{ 1 mol ozygen}} = \text{ 0.01086 mol electrons}

4. Calculate the number of coulombs

t = 8 min 24 s =504 s

Q = It = 504 s × 2.10 C·s⁻¹= 1058 C

5. Calculate the number of electrons

\text{No. of electrons} = \text{1058 C} \times \dfrac{\text{1 electron}}{1.602 \times 10^{-19}\text{ C}} = 6.607 \times 10^{21}\text{ electrons}

6. Calculate Avogadro's number

N_{\text{A}} = \dfrac{6.607 \times 10^{21}}{0.01086} = \mathbf{6.08 \times 10^{23}}\\\\\text{The experimental value of Avogadro's number is } \boxed{\mathbf{6.08 \times 10^{23}}}

3 0
3 years ago
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