All categories

3 years ago

Which type of fermentation produces CO2 bubbles in baking?

Chemistry

1 answer:

Anika [276]3 years ago

6 0

Alcoholic fermentation fermentation produces CO2 bubbles in baking.

Explanation:

The other name given for the Alcoholic Fermentation is Ethanol fermentation. In this process of fermentation, ethanol and carbon dioxide are the resultant by-products. These are formed by the conversion of fructose,sucrose and glucose to cellular energy. This type of fermentation do not require oxygen for the process to take place. Hence, these are known to be an anaerobic process

This type of fermentation has its application like ethanol fuel production, cooking of bread, etc. A dough rises of the Ethanol fermentation. this is because, the sugars that are present in a dough are absorbed by yeast . this produces ethanol and carbon dioxide. During baking process,bubbles are formed by this carbon dioxide.

You might be interested in

What is the mass of 6.75 moles of CO₂?

ikadub [295]

Hi there!
Thank you for choosing Brainly.

1 mole = 44.0095

So take that number and multiply it by 6.75.

You then get... 297.0641

Have a nice day.
~Brooke

8 0

4 years ago

1. What would you need to know in order to predict what color of skin your offspring would have?

Blizzard [7]

Answer:

I believe you would need to know how much melanon you have and how much melanon your partner has. Correct me if i'm wrong. I hope this helps!

6 0

3 years ago

How many moles of argon gas would be present in a 37.0 liter vessel at 45.00 °C at a pressure of 2.50 atm?

Pani-rosa [81]

Answer:

3.54 mol

Explanation:

Step 1: Given data

Volume (V): 37.0 L

Temperature (T): 45.00 °C

Pressure (P): 2.50 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 45.00°C + 273.15 = 318.15 K

Step 3: Calculate the number of moles (n) of argon gas

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 2.50 atm × 37.0 L/(0.0821 atm.L/mol.K) × 318.15 K = 3.54 mol

8 0

3 years ago

Sodium is much more apt to exist as a cation than chlorine because:

8090 [49]

Answer:

(D) chlorine has a greater ionization energy than sodium

Explanation:

Sodium is the element of the group 1 and period 3 which means that the valence electronic configuration is $[Ne]3s^1$ .

Chlorine is the element of the group 17 and period 3 which means that the valence electronic configuration is $[Ne]3s^23p^5$ .

Ionization energy is the minimum amount of energy which is required to knock out the loosely bound valence electron from the isolated gaseous atom.

Thus, removal of one electron in sodium is easy as it will gain noble gas configuration and become stable. But this case does not exist in chlorine and hence, chlorine has a greater ionization energy than sodium.

So,

Sodium is much more apt to exist as a cation than chlorine because chlorine has a greater ionization energy than sodium.

7 0

3 years ago

Which statement best compares the properties of compounds and elements that the compounds contain?

grigory [225]

The answer to this question would be: B.They are different.

A compound will have different characteristics from their element. The interaction of different elements in a compound makes it so. They might have similar or opposite characteristic but it didn't always happen so those answers are not best.

4 0

4 years ago

Read 2 more answers