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2 years ago

Calculate the density of a sample of gas with a mass of 30g and volume of 7500 cm3

Physics

1 answer:

rewona [7]2 years ago

4 0

<span>D= .004 g/ml

Hope this helps!</span>

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2 years ago

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A rocket is fired straight up. It contains two stages (Stage 1 and Stage 2) of solid rocket fuel that are designed to burn for 1

insens350 [35]

Answer: a) 1875m. (b) 8.66s

Explanation:

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2 years ago

If a car accelerates from a speed of 10 m/s at an acceleration of 2 m/s2 for 3s.

Flauer [41]

Answer:

$\boxed{\sf Final \ speed \ of \ the \ car = 16 \ m/s}$

Given:

Initial speed (u) = 10 m/s

Acceleration (a) = 2 m/s²

Time taken (t) = 3s

To Find:

Final speed (v) of the car

Explanation:

From equation of motion we have:

$\boxed{ \bold{v = u + at}}$

By substituting value of u, a & t in the equation we get:

$\sf \implies v = 10 + 2\times 3 \\ \\ \sf \implies v = 10 + 6 \\ \\ \sf \implies v = 16 \: m {s}^{ - 1}$

$\therefore$

Final speed (v) of the car = 16 m/s

3 0

2 years ago

A student used apparatus as shown above. The beaker held 750 g of a liquid. The current from the power supply was 1.8 A and the

liq [111]

Answer:

$2365.71\ \text{J/kg}^{\circ}\text{C}$

Explanation:

V = Voltage = 230 V

I = Current = 1.8 A

$\Delta T$ = Temperature change = $(40-12)^{\circ}\text{C}$

t = Time taken = 2 minutes

m = Mass of liquid = 750 g

c = Specific heat capacity of the liquid

Energy required to heat the water is equal to the heat released due to current passing

$mc\Delta T=VIt\\\Rightarrow c=\dfrac{VIt}{m\Delta T}\\\Rightarrow c=\dfrac{230\times 1.8\times 2\times 60}{0.75\times (40-12)}\\\Rightarrow c=2365.71\ \text{J/kg}^{\circ}\text{C}$

The specific heat capacity of the liquid is $2365.71\ \text{J/kg}^{\circ}\text{C}$

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2 years ago

A cable with a linear density of \mu=0.109~\text{kg/m}μ=0.109 kg/m is hung from telephone poles. The tension in the cable is 572

RUDIKE [14]

Answer:

$f=16.46 Hz$

Explanation:

The equation of the speed of a mechanical wave in terms of the tension and linear density, of the cable in our case, is given by:

$v=\sqrt{\frac{T}{\mu}}$

Where:

T is the tension of the cable (T = 572 N)
μ is the linear density of the cable (μ = 0.109 kg/m)

And we know that v = λ*f

λ is the wavelength
f is the frequency

Because a standing waves pattern is produced that has 4.5 wavelengths between the two poles and the distance between poles is 19.9 meters, the value of the wavelength is: λ = 19.9/4.5 = 4.4 m.

Therefore, the frequency will be:

$\lambda f=\sqrt{\frac{T}{\mu}}$

$f=\frac{1}{\lambda}\sqrt{\frac{T}{\mu}}$

$f=\frac{1}{4.4}\sqrt{\frac{572}{0.109}}$

$f=16.46 Hz$

I hope it helps you!

6 0

2 years ago