The Force on the left hand pole, F' = 0.167N
<h3>What is the force on the left hand pole?</h3>
Force is an agent which produces a change in the motion or state of an object.
Force is a vector quantity.
The general force is calculated as follows:
F = mg/sinθ
m = 17.1 g = 0.0171 kg
g = 9.81 m/s²
θ = 45°
F = 0.0171 * 9.81/sin45
F = 0.237 N
Force on the left hand pole, F' = Fcosθ
F' = 0.237 * cos 45
F' = 0.167N
In conclusion, the force on the left hand pole is the horizontal component of force.
Learn more about force at: brainly.com/question/141439
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Answer:
810 mA
Explanation:
In a series circuit, the current is the same through the system, so if the current through one resistor is 810 mA, the current supplied by the source will be 810 mA.
So, the answer is 810 mA
Answer:
greenhouse gases im pretty sure
Explanation:
If you are asking for the weight then the formula is F=mg where f is weight m is mass and g is acceleration due to gravity.m=52kg and g=9.8m/s2(the gravity of earth)
F=52*9.8=509.6
therefore the weight of the object is 509.6N
10 Km.
S= Speed
D= distance
T= time
S= d/t
but since you are solving for "d" the equation is d=st so you plug in 10 km/h for speed and 2.1 hours for time and just multiply them. The hours cancel out so you are left with 10km.
