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mart [117]
3 years ago
15

a passing warm front changes air pressure. does a passing warm front increase or decrease air pressure

Physics
2 answers:
meriva3 years ago
7 0
Warmer air has molecules more spread out, so I'd say a decrease in air pressure.
Nadusha1986 [10]3 years ago
4 0
Warm air molecules are less dense and spread out more than cool air molecuels so they decreace
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Identify the generic outer electron configuration for the halogens.
Delicious77 [7]
<span>The Halogen outer layer is considered to be full with eight electrons. Halogen is also considered to be part of the Noble gases classification. The exchange of electrons in the halogen atom renders a photon energy pulse with produces light. The consentrated light spectrum is produced in the halogen light bulbs and halogen laser products.</span>
8 0
4 years ago
How can you change your velocity
Anna11 [10]

You could change your velocity by altering both your speed and direction.

For example, if you are running north at 10 miles per hour, and turn into a street going east, then slow down to 5 miles per hour, you would have changed your velocity.

4 0
3 years ago
SOLVE FOR “V”<br> gh=(1/2)(v^2)<br> PLEASE AND THANK YOU!
Alchen [17]

Answer:

square root of 2gh

Explanation:

gh=(1/2)(v^2)

dividing both sides by 1/2, we have

2gh=v^2

therefore;

v=square root of 2gh

5 0
4 years ago
The acceleration due to gravity on planet a is one-sixth what it is on planet b, and the radius of the planet a is one-fourth th
nevsk [136]
The acceleration due to gravity on a large body is given by:
acceleration = (gravitational constant * mass of body) / radius²

For b, this is:
g = GM/r²
M = gr²/G

For a,
g(a) = 1/6 g
r(a) = 1/4 r
M(a) = g(a)r(a)²/G
M(a) = 1/6 g * (1/4 r)²/G
M(a) = gr²/96G

The fraction is given as:
M(a) / M = (gr²/96G) / (gr²/G)
M(a) / M = 1/96

The mass of planet a is 1/96 of the mass of planet b.
8 0
3 years ago
To practice Problem-Solving Strategy 16.1 Standing waves. An air-filled pipe is found to have successive harmonics at 805 Hz , 1
Bingel [31]

Answer: 0.213m

Explanation: The fundamental frequency is 805Hz.

The second harmonic (first overtone ) is 1035 Hz and the third harmonic (second overtone) is 1265 Hz.

The pipe is an air filled hence it is a closed pipe

Recall that v = f λ

At fundamental frequency

Where v = speed of sound in air (v) = 343 m/s

Fundamental frequency (f) = 805 Hz

Wavelength ( λ) = ?

By substituting the parameters, we have that

343 = 805 × λ

λ = 343 / 805

λ = 0.426m

The pipe is an open one and at the fundamental frequency, hence the relationship between wavelength ( λ) and length of air is given as

L = λ/4

But λ = 0.426m

L = 0.426/2

L = 0.213m

6 0
3 years ago
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