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maw [93]
3 years ago
7

After the fission of U-235 takes place, how many neutrons does the missing nucleus have?

Physics
2 answers:
motikmotik3 years ago
4 0

Answer:

B) 85

Explanation:

In the nuclear fission of uranium-235, a nucleus of uranium-235 absorbs a slow-moving neutron and then decays into a nucleus of Kripton-92, a nucleus of Barium-141 (which is the missing nucleus in the figure) and three more neutrons.

Knowing that:

- Uranium has atomic number 92, so it has 92 protons

- Kripton has atomic number 36, so it has 36 protons

- Barium has atomic number 56, so it has 56 protons

We can calculate the number of neutrons in the nucleus of barium, since we know that the total number of neutrons must be conserved. We have:

- On the left side of the reaction: (235-92) neutrons of the uranium + 1 neutron absorbed = 144 neutrons

- On the right side of the reaction: (92-36) neutrons of the krypton + X neutrons of the barium + 3 neutrons = 144

So we get:

56 + X + 3 = 144

X = 85

So, the nucleus of barium has 85 neutrons.


Ivahew [28]3 years ago
3 0
I just finished this question on my test and got it right. 85 is your answer.
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"The equation can be used to calculate the power absorbed by any surface" statement concerning the Stefan-Boltzmann equation is correct.

Answer: Option A

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According to Stefan Boltzmann equation, the power radiated by black body radiation source is directly proportionate to the fourth power of temperature of the source. So the radiation transferred is absorbed by another surface and that absorbed power will also be equal to the fourth power of the temperature. So the equation describes the relation of net radiation loss with the change in temperature from hotter temperature to cooler temperature surface.  

                            P=e \sigma A\left(T^{4}-T_{c}^{4}\right)

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3 years ago
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Gravitational force
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Un hamster esta sentado sobre un tocadisco cuya rapidez angular es constante si el hamster se mueve a un punto localizado al dob
kotegsom [21]

Answer:

b) se duplica

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The disk is moving with constant angular velocity, let's call it \omega.

The linear velocity of a point on the disk is given by

v=\omega r

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In this problem, the object is moved at a distance twice as far as the initial point, so

r' = 2r

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v'=\omega r' = \omega (2r) = 2 \omega r = 2 v

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What is 1/3 of 300​
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6 0
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A particle experiences constant acceleration for 20 seconds
lisabon 2012 [21]

Answer:

The correct answer is D. s₂=4s₁

Explanation:

The distance of a particle is given by:

s=s_{0}+v_{0} t + \frac{1}{2} a t^{2}

where

s₀ is the initial position when t=0

v₀ is the initial speed when t=0

a is the constant acceleration

t is the time in seconds

Then, the position s₁ is given by:

s_{1} = s_{0}+v_{0} t_{1} + \frac{1}{2} a (t_{1})^{2}

As the particle starts from rest v₀=0 and we consider s₀=0, s₁ will be:

s_{1}= \frac{1}{2} a (t_{1})^{2}

Furthermore, the position s₂ is:

s_{2}= \frac{1}{2} a (t_{2})^{2}

In this case t₁=10 s and t₂=20 s (10 seconds later). In other words t₂=2t₁.

We replace the value of  t₂ in the second equation (s₂):

s_{2}= \frac{1}{2} a (t_{2})^{2} \\ s_{2}= \frac{1}{2} a (2t_{1})^{2} \\ s_{2} = \frac{1}{2} a 2^{2}(t_{1})^{2} \\ s_{2} = \frac{1}{2} a 4 t_{1}^{2}

Finally, we divide s₂ by s₁ to get the ratio:

\frac{s_2}{s_1} =\frac{\frac{1}{2}a4t_{1}^{2} }{\frac{1}{2}at_{1}^{2}} =4

\frac{s_2}{s_1}=4 \\  s_{2} = 4 s_{1}

5 0
3 years ago
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