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tigry1 [53]
3 years ago
6

Why cannot sound travel through outer space?

Chemistry
1 answer:
zheka24 [161]3 years ago
7 0
Sound needs an atmosphere to travel around and everyone knows space ain't got an atmosphere, also the speed of sound is 340 metres per second through the air. it travels so much faster on water or solids, but in a vacuum like space there is no matter for the sound to travel through.

hope this helps you good luck
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The production of water proceeds according to the following equation.
ExtremeBDS [4]
The production of water proceeds according to the following equation. 2H2(g) + O2(g) → 2H2O(g). Which describes a way to speed up the collisions between hydrogen and oxygen molecules to produce more water?

Answer: Out of all the options shown above the one that best describes a way to speed up the collisions between hydrogen and oxygen molecules to produce water is answer choice C) Place the reactants in a smaller container.

I hope it helps, Regards.
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4 years ago
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C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate constant, ????
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Answer:

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Explanation:

According to Arrhenius equation for a reaction-

ln(\frac{k_{2}}{k_{1}})=\frac{E_{a}}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})

where k_{2} and k_{1} are rate constants of reaction at T_{2} and T_{1} temperatures (in kelvin) respectively.

E_{a} is activation energy of reaction.

Here T_{1}= 600 K , k_{1}= 6.1\times 10^{-8}s^{-1}

T_{2}= 725 K, E_{a}= 262 kJ/mol and R = 8.314 J/(mol.K)

So plugin all the values in the above equation-

ln(\frac{k_{2}}{6.1\times 10^{-8}s^{-1}})=\frac{262\times 10^{3}J/mol}{8.314J/(mol.K)}\times (\frac{1}{600K}-\frac{1}{725K})

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Hence rate constant at 725 K is 5.2\times 10^{-4}s^{-1}

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4 years ago
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