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telo118 [61]
3 years ago
13

What is the solution set for 7x−3=18 , given the replacement set {0, 1, 2, 3, 4} ?

Mathematics
2 answers:
deff fn [24]3 years ago
7 0

Answer:

the answer is C. X=3

can i have Brainliest

Sveta_85 [38]3 years ago
3 0
Im pretty sure that the answer is b:x=2
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PLEASE HELP!! I do not understand this. And can you explain it for me when I use it again?
damaskus [11]
Let's start b writing down coordinates of all points:
A(0,0,0)
B(0,5,0)
C(3,5,0)
D(3,0,0)
E(3,0,4)
F(0,0,4)
G(0,5,4)
H(3,5,4)

a.) When we reflect over xz plane x and z coordinates stay same, y coordinate  changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.

A(0,0,0)
Reflecting
A(0,0,0)

B(0,5,0)
Reflecting
B(0,-5,0)

C(3,5,0)
Reflecting
C(3,-5,0)

D(3,0,0)
Reflecting
D(3,0,0)


b.)
A(0,0,0)
Moving
A(-2,-3,1)

B(0,-5,0)
Moving
B(-2,-8,1)

C(3,-5,0)
Moving
C(1,-8,1)

D(3,0,0)
Moving
D(1,-3,1)
7 0
3 years ago
Please help me answer this ​
jonny [76]
The answer is 112 im pretty sure!
4 0
3 years ago
Let f(x)=cos(x)x^-2<br> F’(x)=
kondaur [170]

f(x)=cos(x)x^{-2}\implies f(x)=\cfrac{cos(x)}{x^2}\implies \cfrac{df}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{-sin(x)\cdot x^2-cos(x)\cdot 2x}{(x^2)^2}} \\\\\\ \cfrac{df}{dx}=\cfrac{-x[x\cdot sin(x)+2cos(x)]}{x^4}\implies \cfrac{df}{dx}=\cfrac{-[xsin(x)+2cos(x)]}{x^3}

8 0
2 years ago
Check the picture please if you're good at math!!
Jet001 [13]

Answer:

A

Step-by-step explanation:

The triangles aren't similar.

The triangles share a side so we cant use anything involving SSS SAS.

The triangles has only known congruent angle so we cant use AA.

5 0
3 years ago
I need help!
lina2011 [118]

Answer:

25 have a good day

Step-by-step explanation:

8 0
3 years ago
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