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loris [4]
3 years ago
9

In which circumstance is displacement the same as distance traveled?

Chemistry
2 answers:
Ede4ka [16]3 years ago
8 0
Distance travelled will be equal to displacement when the line drawn is completely straight. 

Hopefully, this helps.
inna [77]3 years ago
4 0
<span> an object travels in a straight line, then comes to rest
</span>
You might be interested in
Which of the following reactions could be used to extract the lead from the lead nitrate?
alexgriva [62]

Answer:

Option b. Decomposition

Followed by a reduction process using charcoal

Explanation:

Lead can be obtained from lead nitrate by thermal decomposition of lead nitrate as shown below:

2Pb(NO3)2 —> 2PbO + 4NO2 + O2

The PbO obtained is reduced by charcoal(C) to obtain the metallic Pb as shown below:

2PbO + C —> Pb + CO2

4 0
3 years ago
Calculate the molar mass of B(NO3)3 ?​
Stella [2.4K]

The molar mass of B(NO₃)₃ - Boron nitrate : 196.822 g/mol

<h3>Further explanation</h3>

In stochiometry therein includes  

<em>Relative atomic mass (Ar) and relative molecular mass / molar mass (M)  </em>

So the molar mass of a compound is given by the sum of the relative atomic mass of Ar  

M AxBy = (x.Ar A + y. Ar B)  

The molar mass of B(NO₃)₃ - Boron nitrate :

M B(NO₃)₃ = Ar B + 3. Ar N + 9.Ar O

M B(NO₃)₃ = 10.811 + 3. 14,0067 + 9. 15,999

M B(NO₃)₃ = 196.822 g/mol

7 0
3 years ago
A glucose solution has a density of 1.02 g/ml. what is its specific gravity
Makovka662 [10]
Answer is: specific gravity of glucose is 1,02.
d(glucose) = 1,02 g/ml.
d(water) = 1,00 g/ml.
Specific gravity of glucose = density of glucose ÷ density of water.
Specific gravity of glucose = 1,02 g/ml ÷ 1,00 g/ml.
Specific gravity of glucose = 1,02.
Specific gravity<span> is the ratio of the </span>density<span> of a substance (in this case glucose) to the density of a reference substance (water).</span>
4 0
3 years ago
Read 2 more answers
fish tank initially contains 35 liters of pure water. Brine of constant, but unknown, concentration of salt is flowing in at 5 l
weeeeeb [17]

Answer:

Therefore, the rate of change in the amount of salt is \frac{dx}{dt} =( 5c}{ - \frac{x }{20})

\frac{grams }{min}

Explanation:

Given:

Initial volume of water V = 35 lit

Flowing rate = 5 \frac{Lit}{min}

The rate of change in the amount of salt is given by,

   \frac{dx}{dt} = ( Rate of salt enters tank - rate of sat leaves tank )

Since tank is initially filled with water so we write that,

x(0) = 0

Let amount of salt in the solution is c,

  \frac{dx}{dt} = \frac{5c}{1 } - \frac{x(t) \times 5}{100}

  \frac{dx}{dt} =( 5c}{ - \frac{x }{20}) \frac{grams}{min}

Therefore, the rate of change in the amount of salt is \frac{dx}{dt} =( 5c}{ - \frac{x }{20})

\frac{grams }{min}

7 0
3 years ago
Which of the following phenomena would be associated with the Big Bang theory.
Murrr4er [49]

Answer: justin

Explanation:

It is becasue im rich right

3 0
3 years ago
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