Ask question

Ask question

All categories

2 years ago

9

In which circumstance is displacement the same as distance traveled?

2 answers:

Ede4ka [16]2 years ago

8 0

Distance travelled will be equal to displacement when the line drawn is completely straight.

Hopefully, this helps.

inna [77]2 years ago

4 0

<span> an object travels in a straight line, then comes to rest
</span>

You might be interested in

Which of the following was not a geological clue used to support the theory of continental drift

Andrei [34K]

The answer is:

D. Samples of ocean water.

4 0

2 years ago

Read 2 more answers

What is the temperature in kelvins of -14°C?

julia-pushkina [17]

Answer choice B 259 kelvins

3 0

1 year ago

Balance <br><br> _Mg + _HCL = _MgCl2 + H2

Pavel [41]

_Mg + _HCL = _MgCl2 + H2
Separate the terms on each side:

_Mg + _HCl = _MgCl2 + H2

Mg- 1 Mg-1

H-1 H-2

Cl-1 Cl-2

Mg is balanced on both sides so move on to the next (put a 1 in the space).

1Mg

There are two H's and two Cl's on the results side, so to balance the equation put a 2 as a coefficient for HCl and it'll all balance out.

2HCl

Balamced equation will be:

1Mg + 2HCL = 1MgCl2 + H2

5 0

3 years ago

Read 2 more answers

How are quantum numbers related to atomic orbitals?

sdas [7]

When considering atomic orbitals the only important information they really wanted to know is the size of the orbit, which was described by using quantum numbers.

3 0

2 years ago

What is the molarity (M) of the following solutions?

Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

= 27 + 3(16 + 1)

= 27 + 3(17) = 27 + 51

= 78 g/mole

$Al(OH)_3$ = 78 g/mole

Given mass= 19.2 g/mole

$Mole = \frac{Given\ mass}{Molar\ mass}$

$Mole = \frac{19.2}{78}$

Moles = 0.246

$Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}$

Volume = 280 mL = 0.280 L

$Molarity = \frac{0.246}{0.280)}$

Molarity = 0.879 M

Molarity = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

$Mole = \frac{235.9}{119}$

Moles = 1.98

Volume = 2.6 L

$Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}$

$Molarity = \frac{1.98}{2.6)}$

Molarity = 0.762 M

Molarity = 0.76 M

4 0

2 years ago