All categories

3 years ago

The reaction system

Chemistry

1 answer:

tankabanditka [31]3 years ago

3 0

Answer:

e. As equilibrium is reestablished, the partial pressure of hydrogen decreases.

Explanation:

Hello,

In this case, for the given chemical reaction:

$CS_2(g) + 4H_2(g)\rightleftharpoons CH_4(g) + 2H_2S(g)$

Considering the Le Chatelier's principle which states that adding more reactant shifts the reaction towards the products, condition that is related with the doubling of the hydrogen partial pressure, we can notice that e. As equilibrium is reestablished, the partial pressure of hydrogen decreases since the addition of hydrogen will be used to form more methane and hydrogen sulfide, for that reason, its amount is decreased to reattain equilibrium.

Regards.

You might be interested in

For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia

Fittoniya [83]

Answer : The value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

To calculate the $E^o_{(Cu^{2+}/Cu)}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}$

Putting values in above equation, we get:

$1.10V=E^o_{(Cu^{2+}/Cu)}-(-0.76V)$

$E^o_{(Cu^{2+}/Cu)}=0.34V$

Hence, the value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

8 0

3 years ago

A sample of nitrogen occupies 10.0 liters at 25°C what would be the new volume at 20°C? 7.9 L Ob 9.8 L 10.2 L 10.6 L

PtichkaEL [24]

Answer:

9.4 liter

Explanation:

1) Data:

V₁ = 10.0 L

T₁ = 25°C = 25 + 273.15 K = 298.15 K

P₁ = 98.7 Kpa

T₂ = 20°C = 20 + 273.15 K = 293.15 K

P₂ = 102.7 KPa

V₂ = ?

2) Formula:

Used combined law of gases:

PV / T = constant

P₁V₁ / T₁ = P₂V₂ / T₂

3) Solution:

Solve the equation for V₂:

V₂ = P₁V₁ T₂ / (P₂ T₁)

Substitute and compuite:

V₂ = P₁V₁ T₂ / (P₂ T₁)

V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)

V₂ = 9.4 liter ← answer

You can learn more about gas law problems reading this other answer on

Explanation:

7 0

2 years ago

What is the acknowledgment to ''Do all liquids evaporate at the same rate?'

natita [175]

'Do all liquids evaporate at the same rate
that would be false

4 0

2 years ago

Which is an example of a catalyst? heat stirring decrease in temperature

Lorico [155]

I think the correct answer is decrease in temperature
I feel like that’s the right one

3 0

3 years ago

2. How many moles are contained in 0.800 g of calcium chloride (CaCl2)?

Ronch [10]

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Calcium Chloride, or 110.984 grams.

7 0

3 years ago