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Vikentia [17]
3 years ago
9

What volume would 0.735 moles of O2 gas occupy at STP

Chemistry
1 answer:
tatiyna3 years ago
6 0

Answer:

16.5 dm³

Explanation:

Data Given:

no. moles of O₂ =  0.735 moles

volume of O₂ = ?

Solution:

Now

we have to find volume of O₂ gas

Formula used for this purpose

                   No. of moles = Volume / molar volume

where

molar volume at STP for Oxygen (O₂) = 22.4 dm³/mol

              No. of moles O₂ = Volume of O₂ / 22.4 dm³/mol . . . . . .(1)

Put values in equation 1

                0.735 = Volume of O₂ / 22.4 dm³/ mol

rearrange above equation

              Volume of O₂ = 0.735 x 22.4 dm³/ mol

              Volume of O₂ = 16.5 dm³

So,

the volume of O₂ at STP is 16.5 dm³

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Give the percent yield when 28.16 g of CO2 are formed from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2.
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Answer:

Percentage yield =  25%

Explanation:

Given data:

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Moles of O₂ = 4 mol

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Percentage yield = ?

Solution:

Chemical equation:

2C₈H₁₈ + 25 O₂ → 16CO₂ + 18H₂O

Now we will compare the moles of CO₂ with O₂ and C₈H₁₈.

                 C₈H₁₈     :      CO₂

                     2        :       16

                     4        :       16/2×4=32 mol

                  O₂         :      CO₂

                    25        :      16

                     4         :       16/25×4=2.56 mol

Mass of CO₂:

Mass = number of moles× molar mass

Mass = 2.56 mol ×44 g/mol

Mass = 112.64 g

Percentage yield:

Percentage yield = Actual yield /theoretical yield × 100

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3 years ago
A 1250.0g block of silver at 1oC is placed in 2.6g of water vapor at 102oC. What is the equilibrium temperature of the two subst
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Answer:

Explanation:

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vapor is at 102⁰C

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