Most ___ do not carry electricity well.

As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length

grin007 [14]

Answer:

As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length of your window is Lw. Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity g.

Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward).

Question:

If the bottom of your window is a height hb above the ground, what is the velocity vground of the pot as it hits the ground? You may introduce the new variable vb, the speed at the bottom of the window, defined by

vb=Lwt+gt2.

Express your answer in terms of some or all of the variables hb, Lw, t, vb, and g.

The correct answer is

vground = (t²+lw²+(2t³+2t²)×g×Lw+(t⁴+2t³+t²) ) ∧ 0.5 = vb² +2g×vbt+1/2gt²

Explanation:

We have from the relation

v = u + gt, S = ut + 1/2 gt², v² = u² + 2gS

in this case S = hb, u = vb=Lwt+gt2. and v = vground

therefore v² = (Lwt+gt²)² + 2 × g × hb

= (Lwt+gt²)² + 2 × g × (Lwt+gt²)×t + 1/2 gt² = vb² +2g×vbt+1/2gt²

vground = (t²+lw²+(2t³+2t²)×g×Lw+(t⁴+2t³+t²) ) ∧ 0.5

7 0

3 years ago

The period of a pendulum is the time it takes for the pendulum to make one full back-and-forth swing. The period of a pendulum

mixer [17]

Answer: 0.04 s

Explanation:

The given equation for the period $T$ of a pendulum when the acceleration due gravity is given in feet per squared second $g=32 ft/s^{2}$ is:

$T=2 \pi \sqrt{\frac{l}{32 ft/s^{2}}}$

Where $l=\frac{1}{18} ft$ is the length of the pendulum

$T=2 \pi \sqrt{\frac{\frac{1}{18} ft}{32 ft/s^{2}}}$

$T=0.04 s$

3 0

4 years ago

7)An object is thrown straight up with an initial velocity of 3 m/s. What is its acceleration at its maximum height?

ser-zykov [4K]

C.
It is a motion with uniform acceleration, meaning that the acceleration will not change.
The object is thrown upwards with a positive velocity. This shows that the upward direction is positive. The object will decelerate due to gravity at a magnitude of 9.81 m/s2. Therefore, the acceleration is -9.81 m/s2.
Note that even though the velocity of the object is momentarily 0 m/s at maximum height, there is still a constant acceleration.
This allows the object first decelerate upwards, then change direction at max height, and finally accelerate downwards. So in this case, the acceleration is always negative and unchanged.

7 0

3 years ago

In the process of changing a flat tire, a motorist uses a hydraulic jack. She begins by applying a force of 58 N to the input pi

AfilCa [17]

Answer:

The correct answer is "3899.92 N".

Explanation:

The given values are:

Force,

$F_{app}=58 N$