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Schach [20]
3 years ago
12

Arightward force of 302 N is applied to a 28.6-kg crate to accelerate it across the floor. What will its acceleration be?

Physics
1 answer:
Musya8 [376]3 years ago
8 0

Answer:

a \approx 10.6 m/s²

Explanation:

Since F = ma (Force = mass * acceleration), acceleration would be...

a = F/m

a = 302 N/28.6

a \approx 10.6 m/s²

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A pickup truck has a width of 79.0 in. If it is traveling north at 42 m/s through a magnetic field with vertical component of
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Answer:

The magnitude of the induced Emf is 0.003371V

Explanation:

The width of the truck is given as 79inch but we need to convert to meter for consistency, then

The width= 79inch × 0.0254=2.0066 metres.

Now we can calculate the induced Emf using expresion below;

Then the induced EMF= B L v

Where B= magnetic field component

L= width

V= velocity

=(40*10^-6) × (42) × (2.0066)

=0.003371V

Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V

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4 years ago
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Answer:

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3 years ago
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EleoNora [17]

Answer:

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