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DENIUS [597]
4 years ago
13

When Xavier places his hands near a light bulb, he notices that certain areas around the light bulb are warmer than others. Whic

h best explains this?
Chemistry
2 answers:
goldfiish [28.3K]4 years ago
6 0

Answer:

The region just above the light bulb is warmest due to the phenomenon of convection.

Explanation:

In the given case, as Xavier places his hands close to a light bulb, he feels that some of the regions around the light bulb are warmer in comparison to others. This takes place due to the phenomenon known as convection because of which the region directly above the light bulb gets warmest in comparison to the other regions.  

Convection refers to the transfer of heat with the help of mass movement of fluid like air, and the phenomenon takes place above a hot surface as hot air expands, becomes less dense, and elevates. This thing can be supported by the ideal gas law.  

UNO [17]4 years ago
3 0

The area directly above the light bulb is warmest because of convection.

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OverLord2011 [107]

Answer:

7.54%

Explanation:

A hydrate is a salt that has molecules of water incorporated into the crystals. It is represented by the molecular formula of the salt followed by how many molecules of water it has: XY.nH₂O.

So, the mass of water in the sample will be the difference between the hydrate and the salt without water:

mass of water = 1.034 - 0.956 = 0.078 g

The mass percentage is the mass of water divided by the total mass, and then multiplied by 100%:

(0.078/1.034)x100%

7.54%

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3 years ago
Which section of the reaction represents the products?<br> A) a <br> B) b <br> C) c <br> D) d
vladimir2022 [97]
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When two molecules of methanol (CH3OH) react with oxygen, they combine with three O2 molecules to form two CO2 molecules and fou
Alex17521 [72]

Answer:

188

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3 0
3 years ago
A sample of nitrogen gas occupies 1.55 L at
34kurt

Answer:

The new volume after the temperature reduced to -100 °C is 0.894 L

Explanation:

Step 1: Data given

Volume of nitrogen gas = 1.55 L

Temperature = 27.0 °C = 300 K

The temperature reduces to -100 °C = 173 K

The pressure stays constant

Step 2: Calculate the new volume

V1/T1 = V2/T2

⇒with V1 = the initial volume of the gas = 1.55 L

⇒with T1 = the initial temperature = 300 K

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the reduced temperature = 173 K

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V2 = (1.55L /300K) * 173 K

V2 = 0.894 L

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lina2011 [118]
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