1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Doss [256]
3 years ago
10

Enough of a monoprotic acid is dissolved in water to produce a 0.0147 M solution. The pH of the resulting solution is 2.46. Calc

ulate the pKa for the acid.
Chemistry
1 answer:
Lera25 [3.4K]3 years ago
6 0
First, we need to calculate Ka in order to determine the pKa. 

The formula for Ka = x^2/ initial concentration

initial concentration= 0.0147 M

we need to find x, and we can use the pH to find it because x is the [H+] concentration.

[H+]= 10^-pH----> [H+]= 10^-2.46= 0.00347 

Ka= x^2/ initial---------> (0.00347)^2/ 0.0147= 8.18 x 10^-4

now that we have Ka, we can determine pKa using the following formula--> pKa= -log Ka

pKa= -log (8.18 x 10^-4)= 3.087
You might be interested in
4. Describe how you will measure the volume of a piece of stone​
mariarad [96]

Answer:

One way to measure the volume of any irregular object (in your case, a stone) is to submerge it completely under water and measure the change in the height of the water level. This change in the water level (let's say it goes from 50 mL to 65 mL) indicates that the stone has a volume of 15 mL.

3 0
2 years ago
What is the correct formula for calcium nitride
Artemon [7]
Ca3N2 is your answer<span> </span>
8 0
3 years ago
What is the atomic mass equal to?
mixer [17]

Atomic mass is equal to the total number of electrons  neutrons and protons

8 0
2 years ago
Read 2 more answers
Now that Snape and Dumbledore has taught you the finer points of hydration calculations they have a slightly more challenging pr
Mrrafil [7]

Answer:

The value of an integer x in the hydrate is 10.

Explanation:

Molarity=\frac{Moles}{Volume(L)}

Molarity of the solution = 0.0366 M

Volume of the solution = 5.00 L

Moles of hydrated sodium carbonate = n

0.0366 M=\frac{n}{5.00 L}

n=0.0366 M\times 5 mol=0.183 mol

Mass of hydrated sodium carbonate = n= 52.2 g

Molar mass of hydrated sodium carbonate = 106 g/mol+x18 g/mol

n=\frac{\text{mass of Compound}}{\text{molar mass of compound}}

0.183 mol=\frac{52.2 g}{106 g/mol+x\times 18 g/mol}

106 g/mol+x\times 18 g/mol=\frac{52.2 g}{0.183 mol}

Solving for x, we get:

x = 9.95 ≈ 10

The value of an integer x in the hydrate is 10.

6 0
3 years ago
Identify h2so4(aq) as an acid or a base. write a chemical equation showing how this is an acid according to the arrhenius defini
yarga [219]
  H2SO4  is an  acid

the  chemical  equation  showing  how H2SO4  is an acid  according  to the Arrhenius  definition   is as below

H2SO4  dissociate to  give  2H^+  and  SO4^2-

that is   H2SO4  = 2H^+  +  SO4^2-

According to Arrhenius  an acid  dissociate  to give H^+  ions H2SO4 is an acid  since  it dissociate  to  give  two hydrogen ions  
4 0
3 years ago
Read 2 more answers
Other questions:
  • what force is necessary for a zookeeper to lift a sedated lion with a total mass of 175 kg with an upward acceleration of .65 m/
    9·1 answer
  • Which of these is NOT a physical change?
    6·1 answer
  • Josh is making homemade lollipops. the recipe calls for dissolving 400 g sugar in 100 g of water. his friend, alex, said that wo
    8·2 answers
  • Five different substances are given to you to be dissolved in water. which substances are most likely to undergo dissolution in
    11·2 answers
  • PLEASE ANSWER ASAP
    8·2 answers
  • At 27.00 °c a gas has a volume of 6.00 L . What will the volume be at 150.0 °c
    7·1 answer
  • What is formula of matter
    13·1 answer
  • Please answer
    10·1 answer
  • Arrange the compounds from lowest boiling point to highest boiling point.
    6·1 answer
  • B) Wax is a solid at room temperature. Air is a gas. Air's density is 1.30kg/m³
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!