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Doss [256]
3 years ago
10

Enough of a monoprotic acid is dissolved in water to produce a 0.0147 M solution. The pH of the resulting solution is 2.46. Calc

ulate the pKa for the acid.
Chemistry
1 answer:
Lera25 [3.4K]3 years ago
6 0
First, we need to calculate Ka in order to determine the pKa. 

The formula for Ka = x^2/ initial concentration

initial concentration= 0.0147 M

we need to find x, and we can use the pH to find it because x is the [H+] concentration.

[H+]= 10^-pH----> [H+]= 10^-2.46= 0.00347 

Ka= x^2/ initial---------> (0.00347)^2/ 0.0147= 8.18 x 10^-4

now that we have Ka, we can determine pKa using the following formula--> pKa= -log Ka

pKa= -log (8.18 x 10^-4)= 3.087
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From the Henderson-Hasselbalch equation, explain how the ratio [Al/[HA] changes with changing pH
Kryger [21]

Answer:

The ratio [A-]/[HA] increase when the pH increase and the ratio decrease when the pH decrease.

Explanation:

Every weak acid or base is at equilibrium with its conjugate base or acid respectively when it is dissolved in water.

HA + H_{2}O ⇄ A^{-} + H_{3}O^{+}

This equilibrium depends on the molecule and it acidic constant (Ka). The Henderson-Hasselbalch equation,

pH = pKa + Log \frac{[A^{-}]}{[HA]}

shows the dependency between the pH of the solution, the pKa and the concentration of the species. If the pH decreases the concentration of protons will increase and the ratio between A- and AH will decrease. Instead, if the pH increases the concentration of protons will decreases and the ratio between A- and AH will increase.

5 0
3 years ago
2L of hydrogen has an initial pressure of 750 mmHg, what is the final pressure in mmHg if the volume increases to 20 L with a co
Verdich [7]

Answer: The final pressure is 75 mm Hg.

Explanation:

According to Boyle's law, at constant temperature the pressure of a gas in inversely proportional to volume.

Since, it is given that the temperature is constant. Hence, formula used is as follows.

P_{1}V_{1} = P_{2}V_{2}

Substitute the values into above formula as follows.

P_{1}V_{1} = P_{2}V_{2}\\750 mm Hg \times 2 L = P_{2} \times 20 L\\P_{2} = \frac{750 mm Hg \times 2 L}{20 L}\\= 75 mm Hg

Thus, we can conclude that the final pressure is 75 mm Hg.

3 0
3 years ago
A gas exerts a pressure of 0.62 atm. Convert this to kPa and mmHg. Be sure to show your work.
IRINA_888 [86]

Answer:

The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg

Explanation:

Data

P = 0.62 atm

P = ? kPa

P = ? mmHg

Process

1.- Look for the conversion factor of atm to kPa and mmHg

 1 atm = 101.325 kPa

1 atm = 760 mmHg

2.- Do the conversions

                  1 atm ----------------- 101.325 kPa

                  0.62 atm ------------  x

                   x = (0,62 x 101.325) / 1

                  x = 62.82 kPa

                   1 atm ------------------ 760 mmHg

                   0.62 atm ------------  x

                   x = (0.62 x 760)/1

                   x = 471.2 mmHg                

4 0
3 years ago
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An Insulator.

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_____ is the measurement of the density of a substance as compared to water.
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Answer: Specific gravity
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