It’s fluorine it has a big jump from the 6th to 7th ionisation energy.
It’s electronic configuration is 1s2 2s2 2p5 as it has 9 electrons and 7 electrons in outermost shell.
Therefore it’s in group 7, as after the 7 electrons are removed, the 8th electron is removed from a quantum shell closer to the nucleus.
This results in greater ionisation energy due to stronger electrostatic forces of attraction between positively charge nuclei and electrons ( + shorter distance)
Od. 0-0 does not pair of the Molecules bid it’s polar bond due to certain pairs of molecules not being present within its presentations
Answer:
Sodium is extracted from it's ore by electrolysis of fused sodium chloride.
Explanation:
he process is usually carried out ia a special electrochemical cell called the downs cell. While molten sodium metal is collected at the cathode and also sent to tanks for cooling and storage.
The complete balanced chemical reaction is:
2 AgNO3 + Na2S --> 2 NaNO3 + Ag2S
First let us calculate the number of moles of AgNO3.
moles AgNO3 = 0.315 M * 0.035 L
moles AgNO3 = 0.011025 mol
From the reaction, 1 mole of Na2S is needed for every 2
moles of AgNO3 hence:
moles Na2S required = 0.011025 mol AgNO3 * (1 mol Na2S / 2
mol AgNO3)
moles Na2S required = 5.5125 x 10^-3 mol
Therefore volume required is:
volume Na2S = 5.5125 x 10^-3 mol / 0.260 M
<span>volume Na2S = 0.0212 L = 21.2 mL</span>
Answer:
My guess would be 12.5828
