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Artemon [7]
3 years ago
7

A 590-kg rocket is at rest on the launch pad. what upward thrust force is needed to accelerate the rocket uniformly to an upward

speed of 28 m/s in 3.3 s?
Physics
2 answers:
fgiga [73]3 years ago
5 0

<u>Answer:</u> The upward thrust force needed is 5003.2 N

<u>Explanation:</u>

Acceleration is defined as the rate of change of velocity with respect to time.

Mathematically,

a=\frac{v-u}{t}

where,

v = final velocity = 28 m/s

u = initial velocity = 0 m/s

t = time taken = 3.3 s

Putting values in above equation, we get:

a=\frac{28-0}{3.3}=8.48m/s^2

Force is defined as the push or pull on an object with some mass that causes change in its velocity.

It is also defined as the mass multiplied by the acceleration of the object.

Mathematically,

F=m\times a

where,

F = force exerted on the rocket = ?

m = mass of the rocket = 590 kg

a = acceleration of the rocket = 8.48m/s^2

Putting values in above equation, we get:

F=590kg\times 8.48m/s^2\\\\F=5003.2N

Hence, the upward thrust force needed is 5003.2 N

BARSIC [14]3 years ago
3 0
V(final)=V₀+a(t), V(final)=28, V₀=0, t=3.3, solve for a. a=28/3.3=8.5m/s^2. F=ma, F=?, m=590kg, a=8.5m/s^2, F=5015N. 
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Explanation:

Given

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F=\frac{kQ^2}{r^2}

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F'=\frac{k2Q\cdot 2Q}{\frac{r^2}{2^2}}

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Answer:

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