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Alenkasestr [34]
2 years ago
11

__________ is when all light rays bounce off an object at the same angle.

Physics
1 answer:
Ad libitum [116K]2 years ago
5 0
Diffuse reflection have a great day

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an object has a length of 5.0 cm, aheight of 3.0 cm and a width of 15.0 cm. it has a mass of 24 grams. what is its density?
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5x3=N
Nx15=F
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I need help on this question
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there are 5 hydrogen atoms in that formula

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How much work will be done on a 30kg object traveling at 20 m/s from the rest?
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Two identical rifles are shot at the same time, and the sound intensity level is 64.7 dB. What would be the sound intensity leve
mixas84 [53]

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The sound intensity is still the same. The sound intensity level does not depend on the number of sound sources but only the wave properties of the wave medium and the properties of the sound source. The wave properties of the medium includes the density and also the temperature.

Explanation:

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2 years ago
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A mass weighing 4 pounds is attached to a spring whose constant is 2 lb/ft. The medium offers a damping force that is numericall
Ad libitum [116K]

Answer:

t = 025 s

Explanation:

We know

weight, W =  4 pounds

spring constant, k = 2 lb/ft

Positive damping, β = 1

Therefore mass,  m =  W / g

                             m = 4 / 32

                                  = 1 / 8 slug

From Newtons 2nd law

\frac{d^{2}x}{dt^{2}}=-kx-\beta .\frac{dx}{dt}

where x(t) is the displacement from the mean or equilibrium position. The equation can be written as

\frac{d^{2}x}{dt^{2}}+\frac{\beta }{m}.\frac{dx}{dt}+\frac{k}{m}x=0

Substituting the values, the DE becomes

\frac{d^{2}x}{dt^{2}}+8\frac{dx}{dt}+16x=0

Now the equation is

m^{2}+8m+16=0

and on solving the roots are

m_{1} = m_{2} = -4

Therefore the general solution is x(t)=e^{-4t}\left ( c_{1}+c_{2}t \right )

Now for initial condition x(0) = -1 ft

                                        x'(0)= 8 ft/s

Now we can find the equation of motion becomes,

x(t)=e^{-4t}\left ( -1+4t \right )

Therefore, the mass passes through the equilibrium when

x(t) = 0

e^{-4t}\left ( -1+4t \right ) = 0

-1+4t = 0

t = \frac{1}{4}

  = 0.25 s

8 0
2 years ago
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