Gabe and his mom caught 4 fish and brought them home for dinner. Before cooking the fish,

Which expression is a prime polynomial?A. X^3-bx^2B. X^2-4x-12C. X^+8xy^3D. X^2-b^3

SOVA2 [1]

A prime polynomial is one that can only be divided by itself and 1. Let's check it option.

A. x³-bx²

This polynomial can be divided by itself, 1, x and x². So it can't be prime.

B. x²-4x-12

This polynomial represents the standard form of a second order polynomial. This means that it is a parabolla. A polynomial of this form can be divided by (x-a) where "a" is the value of its roots. So it can't be prime.

C. x+8xy³

This polynomial can be divided by x, 1 and itself, therefore it can't be a prime.

D. x²-b³

This polynomial can only be divided by 1 and itself. So this is the correct answer.

5 0

2 years ago

If m ∠ 1 = 101, what is the value of X?

tankabanditka [31]

The value of x is the value of x :)

3 0

3 years ago

What is the standard form of the equation of the circle x^2 - 2x + y^2 - 8y + 8 = 0?

lesantik [10]

Answer:

Step-by-step explanation:

Begin by grouping the x terms and the y terms together and separating the constants out.

$(x^2-2x)+(y^2-8y)=-8$

Now we'll complete the square on those x and y terms. Take half the linear term of each, square it, and add it to both sides. Our linear x term is 2, half of 2 is 1 and 1 squared is 1, so we add that in. Likewise, half the linear y term (which is 8) is 4, and 4 squared is 16, so we add that in, too. Like this:

$(x^2-2x+1)+(y^2-8x+16)=-8+1+16$

Doing this gives us the perfect square binomials for each of the x and y terms, and then gives us the radius on the right:

$(x-1)^2+(y-4)^2=9$

This is a circle with a center of (1, 4) and a radius of 3.

4 0

3 years ago

All steps for: x/x-2 + x-1/x+1= -1

lorasvet [3.4K]

Answer:

$\large\boxed{x=0\ \vee\ x=1}$

Step-by-step explanation:

$Domain:\\\\x-2\neq0\ \wedge\ x+1\neq0\\\\x\neq2\ \wedge\ x\neq-1\\\\\boxed{D:\ x\in\mathbb{R}-\{-1,\ 2\}}\\\\=============================$

$\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1\qquad\text{subtract}\ \dfrac{x-1}{x+1}\ \text{from both sides}\\\\\dfrac{x}{x-2}=-1-\dfrac{x-1}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-(x+1)}{x+1}+\dfrac{-(x-1)}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-(x+1)-(x-1)}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-x-1-x+1}{x+1}\\\\\dfrac{x}{x-2}=\dfrac{-2x}{x+1}\qquad\text{cross multiply}$

$x(x+1)=-2x(x-2)\qquad\text{use the distributive property}\\\\(x)(x)+(x)(1)=(-2x)(x)+(-2x)(-2)\\\\x^2+x=-2x^2+4x\qquad\text{add}\ 2x^2\ \text{to both sides}\\\\3x^2+x=4x\qquad\text{subtract 4x from both sides}\\\\3x^2-3x=0\qquad\text{distributive}\\\\3x(x-1)=0\iff 3x=0\ \vee\ x-1=0\\\\x=0\in D\ \vee\ x=1\in D$

4 0

3 years ago

Read 2 more answers

The line of best fit for a graph is y = 0.5x + 20. Based on that function, what would you expect to happen at x = 10?

Sedaia [141]

Answer: help

Step-by-step explanation:

did you figure the problem out

3 0

3 years ago